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nasty-shy [4]
3 years ago
8

Sue read 129 pages. Mary read 74 pages. How many more pages did Sue read than Mary?

Mathematics
2 answers:
Ber [7]3 years ago
7 0

sue read 55 more pages then mary

ozzi3 years ago
5 0

To solve this, you see that Sue read 129 and mary read 74. The equation       129-74=? would find the answer. The answer is that Sue read 55 more pages in the book than Mary.

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  1. Angle 1 is congruent to angle 2, since BD bisects <ABC and the two angles created on each side of the bisector at point B are equal.
  2. <2 ≅ <3 because of the corresponding angles theorem.
  3. <1 ≅ <4 because alternate angles are congruent if two parallel lines are cut by a transversal.
  4. <3 ≅ <4 by the substitution property of equality.
  5. AD/CD = EB/CB by the triangle proportionality theorem.
  6. If two angles in a triangle are congruent, the sides opposite the angles are congruent, so AE = EB.
  7. AD/CD = AB/CB by the substitution property of equality.

<h3>The properties of similar triangles.</h3>

In Geometry, two (2) triangles are said to be similar when the ratio of their corresponding side lengths are equal and their corresponding angles are congruent.

<h3>What is the substitution property of equality?</h3>

The substitution property of equality states that assuming x, y, and z are three (3) quantities, and if x is equal to y (x = y) based on a rule and y is equal to z (y = z) by the same rule, then, x and z (x = y) are equal to each other by the same rule.

In this context, we can reasonably infer and logically deduce that the ratio of AD/CD is equal to AB/CB based on the substitution property of equality.

Read more on substitution property here: brainly.com/question/2459140

#SPJ1

Complete Question:

In ΔABC, side BC is extended to point E. When connected to vertex A, segment EA is parallel to segment BD. In this construction, you are given that BD bisects <ABC.

Prove: AD/CD = AB/CB.

Complete the paragraph proof.

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lesya [120]
The answer is B ....
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gtnhenbr [62]

Answer:

c. 6

Step-by-step explanation:

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