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Eva8 [605]
2 years ago
12

Vanadium v hydroxide formula

Chemistry
1 answer:
Mila [183]2 years ago
8 0

Molecular Formula: H5O5V-5

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0.500 L of a gas is collected at 2911 MM and 0°C. What will the volume be at STP?
ioda

Answer:

V₂ =  1.92 L

Explanation:

Given data:

Initial volume = 0.500 L

Initial pressure =2911 mmHg (2911/760 = 3.83 atm)

Initial temperature = 0 °C (0 +273 = 273 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

by putting values,

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 3.83 atm × 0.500 L × 273 K / 273 K × 1 atm

V₂ = 522.795 atm .L. K / 273 K.atm

V₂ =  1.92 L

4 0
3 years ago
ANSWER FAST PLZ!!!!!!!!!
valina [46]
I think the answer is B
7 0
2 years ago
Read 2 more answers
A piece of material with a mass of 755 g is heated to 84.5 c and added to 50 g of water at 5
lana [24]
Alright sorry you're getting the answer hours later, but i can help with this.
so you're looking for specific heat, the equation for it is <span>macaΔTa = - mbcbΔTb with object a and object b. that's mass of a times specific heat of a times final minus initial temperature of a equals -(mass of b times specific heat of b times final minus initial temperature of b)
</span>so putting in your values is, 755g * ca * (75 celsius - 84.5 celsius) = -(50g * cb * (75 celsius - 5 celsius))
well we know the specific heat of water is always 4180J/kg celsius, so put that in for cb
with a bit of simplification to the equation by doing everything on each side first you have, -7172.5 * ca = -14630000
divide both sides by -7172.5 so you can single out ca and you get, ca= 2039.74
add units for specific heat which are J/kg celsius and the specific heat of the material is 2039.74 J/kg celsius

6 0
3 years ago
How many grams of copper
iren [92.7K]
  • <u>The</u><u> </u><u>mas</u><u> </u><u>of copper</u><u> </u><u>is</u><u> </u><u>217</u><u>.</u><u>3</u><u> </u><u>grams</u><u>.</u>
7 0
2 years ago
How much would you need to weigh out in order to have 0.2moles of magnesium atoms?
muminat
X/24=0.2moles
x=4.8gram of magnesium is needed to have 0.2 moles of Mg
5 0
2 years ago
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