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3 years ago

15

The percentage of carbon dioxide in the atmosphere has increased in the last century and is a concern for the environment as it

increases the greenhouse effect. Give one possible explanation for the increase of carbon dioxide in the atmosphere

1 answer:

erma4kov [3.2K]3 years ago

5 0

When fossil fuels are burned for energy, carbon that was sequestered underground is being released again into the atmosphere.

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Determine the mass of carbon iv oxide ,produced on burning 104g of ethyne

mars1129 [50]

163 grams (3 sig. fig.).

<h3>Explanation</h3>

Formula of <em>carbon(IV) oxide</em> (a.k.a. carbon dioxide): $\text{CO}_2$ .
Molar mass of $\text{CO}_2$ : $\underbrace{12.01}_{\text{C}} + 2\times\underbrace{16.00}_{\text{O}}=44.01\;\text{g}\cdot\text{mol}^{-1}$ .

Formula of ethyne: structural $\text{H}-\text{C}\equiv\text{C}-\text{H}$ or molecular $\text{C}_2\text{H}_2$ .
Molar mass of $\text{C}_2\text{H}_2$ : $2\times\underbrace{12.01}_{\text{C}}+2 \times\underbrace{16.00}_{\text{O}} = 56.02\;\text{g}\cdot\text{mol}^{-1}$ .

All carbon atoms in that 104 grams of ethyne will end up in $\text{CO}_2$ . Number of moles of molecules in 104 grams of ethyne:

$n = \dfrac{m}{M} = \dfrac{104}{56.02} = 1.85648\;\text{mol}$ .

There are two carbon atoms in each ethyne molecule. Number of carbon atoms in that many ethyne molecules:

$n(\text{C}) = 2\;n(\text{C}_2\text{H}_2) = 3.71296\;\text{mol}$ .

There are one carbon atom in each $\text{CO}_2$ molecule. In case oxygen is in excess, all those carbon atoms from that 104 grams of ethyne will make $n(\text{CO}_2) = n(\text{C}) =3.71296\;\text{mol}$ of $\text{CO}_2$ .

Mass of all those $\text{CO}_2$ molecules:

$m = n\cdot M = 163\;\text{g}$ . (3 sig. fig. as in the mass of ethyne.)

7 0

4 years ago

if 1.386 g of mg ribbon combusts to form 2.309 g of oxide product, calculate the experimental mass percent of oxygen from this d

Pavlova-9 [17]

1.386 g of Mg ribbon combusts to form 2.309 g of oxide product. The mass percent of oxygen in the oxide is 40.0 %.

Let's consider the reaction for the combustion of Mg.

Mg + 1/2 O₂ ⇒ MgO

1.386 g of Mg combusts to form 2.309 g of MgO. We want to determine the mass of oxygen in MgO. According to Lavoisier's law of conservation of mass, matter is not created nor destroyed over the course of a chemical reaction. Then, the mass of Mg in the reactants is equal to the mass of Mg in MgO. The mass of the magnesium oxide is the sum of the masses of magnesium and oxygen. The <u>mass of oxygen in the oxide</u> is:

$mMgO = mMg + mO\\mO = mMgO - mMg = 2.309 g - 1.386 g = 0.923 g$

We can calculate the mass percent of O in MgO using the following expression.

$\% O = \frac{mO}{mMgO} \times 100\% = \frac{0.923 g}{2.309g} \times 100\% = 40.0 \%$

You can learn more about mass percent here: brainly.com/question/14990953

3 0

2 years ago

. Mitosis allows one cell to grow and split into 2 new cells. Will those 2 new cells split again explain.

Finger [1]

Answer:

Yes

Explanation:

They continue to split and grow and split again until the organism that is carrying them dies.

Sorry I don't really know how to explain:(

4 0

3 years ago

Examine the statement about alchemy

Arturiano [62]

Answer: B.

Explanation:

7 0

3 years ago

The air above earth’s surface is at different temperatures. What is responsible for this difference in temperature?

tino4ka555 [31]

The Mesosphere, like the troposphere layer, has a decrease in temperature with altitude because of the decreases in the density of the air molecules. Thermosphere: As the altitude increases, the air temperature increases.

3 0

3 years ago

Read 2 more answers