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Yanka [14]
3 years ago
15

The percentage of carbon dioxide in the atmosphere has increased in the last century and is a concern for the environment as it

increases the greenhouse effect. Give one possible explanation for the increase of carbon dioxide in the atmosphere
Chemistry
1 answer:
erma4kov [3.2K]3 years ago
5 0
When fossil fuels are burned for energy, carbon that was sequestered underground is being released again into the atmosphere.
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Anastaziya [24]

Answer:

3) Warm Temperatures and High pressures

Explanation:

This is the typical characteristic of southern air masses moving north

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3 years ago
1. a Use the valence electron molecular orbital diagram for F2 to propose ground state F2ions that satisfy the following conditi
ikadub [295]
If 2.34 moles of Mg react with 3.56 moles of l2 and 1.76 moles of Mgl2 form, what is the percent yield?
3 0
2 years ago
Explain why it is advantageous that water does not evaporate quickly on earth<br><br> PLEASE HELP!!
stich3 [128]

Answer:

When the humidity is 100 percent, the air is saturated with water. Air pressure also affects evaporation. If air pressure is high on the surface of a body of water, then the water will not evaporate easily. The pressure pushing down on the water makes it difficult for water to escape into the atmosphere as vapor.

Explanation:

6 0
2 years ago
Using any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 30.0 °C for the following reacti
gayaneshka [121]

Answer : The value of K for this reaction is, 2.6\times 10^{15}

Explanation :

The given chemical reaction is:

CH_3OH(g)+CO(g)\rightarrow HCH_3CO_2(g)

Now we have to calculate value of (\Delta G^o).

\Delta G^o=G_f_{product}-G_f_{reactant}

\Delta G^o=[n_{HCH_3CO_2(g)}\times \Delta G^0_{(HCH_3CO_2(g))}]-[n_{CH_3OH(g)}\times \Delta G^0_{(CH_3OH(g))}+n_{CO(g)}\times \Delta G^0_{(CO(g))}]

where,

\Delta G^o = Gibbs free energy of reaction = ?

n = number of moles

\Delta G^0_{(HCH_3CO_2(g))} = -389.8 kJ/mol

\Delta G^0_{(CH_3OH(g))} = -161.96 kJ/mol

\Delta G^0_{(CO(g))} = -137.2 kJ/mol

Now put all the given values in this expression, we get:

\Delta G^o=[1mole\times (-389.8kJ/mol)]-[1mole\times (-163.2kJ/mol)+1mole\times (-137.2kJ/mol)]

\Delta G^o=-89.4kJ/mol

The relation between the equilibrium constant and standard Gibbs, free energy is:

\Delta G^o=-RT\times \ln K

where,

\Delta G^o = standard Gibbs, free energy  = -89.4 kJ/mol = -89400 J/mol

R = gas constant  = 8.314 J/L.atm

T = temperature  = 30.0^oC=273+30.0=303K

K = equilibrium constant = ?

Now put all the given values in this expression, we get:

-89400J/mol=-(8.314J/L.atm)\times (303K)\times \ln K

K=2.6\times 10^{15}

Thus, the value of K for this reaction is, 2.6\times 10^{15}

4 0
3 years ago
Children tend to resemble their parents in many ways; they may have like eye color, hair texture, height, or skin tone. This is
weeeeeb [17]

black would be BB .

dominant gene is B.

phenotyope is where it says white fur.

recessive gene is b.

white is bb

5 0
2 years ago
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