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zzz [600]
3 years ago
6

5. If W(-10, 4), X(-3,-1), and Y(-5, 11) classify AWXY by its sides. Show all work to justify your

Mathematics
1 answer:
Ierofanga [76]3 years ago
3 0

Answer:

  an isosceles right triangle

Step-by-step explanation:

The square of the length of a side can be found from the distance formula:

  d^2 = (x2-x1)^2 +(y2-y1)^2

The square of the length of WX is ...

  WX^2 = (-3-(-10))^2 +(-1-4)^2 = 49+25 = 74

The square of the length of XY is ...

  XY^2 = (-5-(-3))^2 +(11-(-1))^2 = 4 +144 = 148

The square of the length of YW is ...

  YW^2 = (-10-(-5))^2 +(4 -11)^2 = 25 +49 = 74

The sum of the squares of the short sides is equal to the square of the long side, so this is a right triangle. The squares of the short sides are equal, so this is an isosceles right triangle.

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Answer:
Y= -4 :)

Steps:
Apply rule
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7 0
3 years ago
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A 12-foot ladder leans against the wall; the base of the ladder is 2 feet away from the wall.To the nearest tenth of a foot, how
ludmilkaskok [199]
<h3>The ladder will reach a height of 11.8 feet up the wall</h3>

<em><u>Solution:</u></em>

The ladder, wall and base of the ladder from wall forms a right angled triangle

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Length of ladder = 12 foot

base of the ladder from wall = 2 feet

<em><u>To find: height of wall</u></em>

By pythagoras theorem.

c^2 = a^2+b^2

Where,

"c" is the Length of ladder

"a" is the base of the ladder from wall

"b" is the height of wall

Substituting the values,

12^2 = 2^2+b^2\\\\144 = 4 + b^2\\\\b^2 = 140\\\\b = \pm 11.832 \\\\Ignore\ negative\ value\\\\b \approx 11.8

Thus, the ladder will reach a height of 11.8 feet on wall

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Step-by-step explanation:

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Step-by-step explanation:

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