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zzz [600]
3 years ago
6

5. If W(-10, 4), X(-3,-1), and Y(-5, 11) classify AWXY by its sides. Show all work to justify your

Mathematics
1 answer:
Ierofanga [76]3 years ago
3 0

Answer:

  an isosceles right triangle

Step-by-step explanation:

The square of the length of a side can be found from the distance formula:

  d^2 = (x2-x1)^2 +(y2-y1)^2

The square of the length of WX is ...

  WX^2 = (-3-(-10))^2 +(-1-4)^2 = 49+25 = 74

The square of the length of XY is ...

  XY^2 = (-5-(-3))^2 +(11-(-1))^2 = 4 +144 = 148

The square of the length of YW is ...

  YW^2 = (-10-(-5))^2 +(4 -11)^2 = 25 +49 = 74

The sum of the squares of the short sides is equal to the square of the long side, so this is a right triangle. The squares of the short sides are equal, so this is an isosceles right triangle.

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3 years ago
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NEED The FULL equation. Will give Brainly. Thank you!
Ghella [55]

Answer:

\displaystyle  \sf h( - 1) =   - \frac{    2}{3}

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we are given a function

\displaystyle \sf h(x) =  \frac{2x - 6}{4 {x}^{2}  + 8}

we would like to simplify it for h(-1)

in order to do so

substitute the value of x

\displaystyle \sf h( - 1) =  \frac{2 \cdot - 1- 6}{4 { (- 1)}^{2}  + 8}

by order of PEMDAS

simplify square:

\displaystyle \sf h( - 1) =  \frac{2 \cdot - 1- 6}{4 { ( 1)}^{}  + 8}

simplify multiplication:

\displaystyle \sf h( - 1) =  \frac{ - 2 - 6}{4 { }^{}  + 8}

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