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NeTakaya
3 years ago
10

Help easy math I think

Mathematics
2 answers:
Ne4ueva [31]3 years ago
6 0

Answer:

circle- 1/2 kahooooot!

Step-by-step explanation:

From A,B,C to A',B',C'

is .5 or 1/2

Artemon [7]3 years ago
6 0

Answer:it The blue one

Step-by-step explanation:

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A rocket moves through outer space at 10,500 m/s. At this rate how much time would be required to travel the distance from Earth
Orlov [11]

Answer:

The answer is around 27.63 seconds.

Step-by-step explanation:

1 km equals 1000 meters so we have to multiply 10,500 and 1,000 which would equal 10,500,000 km. 10,500,000 divided by 380,000 which is around 27.63 seconds.

8 0
3 years ago
Read 2 more answers
1.6 hours to 0.95 hour increase and decrease?? also show the work.. thxs!
notka56 [123]

Answer:

Decrease

Step-by-step explanation:

If you look at the numbers in general 1.6 has a one in it. Meanwhile 0.95 is part of one. Think of it as money. Which would you rather have $1.60 or 0.95 cents.

5 0
3 years ago
5 <br> 2<br> +(12−7+x) if x=6
steposvetlana [31]

Answer:

the answer will be 6 or 10

7 0
3 years ago
Plz Help NO LINKS NO LINKS
Ann [662]

Answer:

The second one is correct.

6 0
3 years ago
For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
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