Answer:
the slope is 3/2
the x intercept is (-1/3,0)
the y intercept is (0, 1/2)
The equation x squared minus 8x+16 represents the data in the graph because if you use the -b/2a x=4. Then if you plug in the 4 for the x in the equation you would come out with the vertex of (4,0). Hope this helps.
f(x)= -x^2+4 plotted vertex (0,4)
Our angle teta is:
teta = 3pi/4
since that is larger than pi/2 but less than pi that means that our angle lies in II quadrant (x negative y positive)
sin(3pi/4) = √2/2
cosine and tangent of that angle must be negative because of position of the angle.
cos(3pi/4) = -√2/2
tan(3pi/4) = -1
