Ask question

Ask question

All categories

3 years ago

9

8x^2+2x^3-6x-14 what's the answer

1 answer:

Shtirlitz [24]3 years ago

3 0

8x^2 + 2x^3 - 6x - 14
Reordering..
2x^3 - 8x^2 - 6x - 14
We can halve everything
x^3 - 4x^2 - 3x - 7
We can then factorize -4x^2 - 3x - 7
to make (-4x - 7)(x - 1)
= x^3 + (-4x - 7)(x - 1)
I don't know how to simplify it further than that.. sorry

You might be interested in

HELP 276.5 divided by 7.9.

cestrela7 [59]

Answer:

35

Step-by-step explanation:

276.5 / 7.9 X 10 = 2765 /79 = 35

4 0

3 years ago

Read 2 more answers

If you ask a question will the points given ne deducted from your points

Lerok [7]

Answer:

I think so yeah. not sure though

6 0

3 years ago

Read 2 more answers

Chantel travels 300 miles in 6 hours and 200 miles in 4 hours. What would the slope of the function find? What would the unit be

zaharov [31]

(4,200)(6,300)
slope = (300 - 200) / (6 - 4) = 100/2 = 50 <== slope

unit rate is 50 miles per hr

5 0

3 years ago

find the area of the isocele triangle formed by the points of intersection of parabolas y=-x^2+9 and y=2x^2-3 and the origin

leonid [27]

Answer:

$10\ \text{sq. units}$

Step-by-step explanation:

The parabola's are

$y=-x^2+9$

$y=2x^2-3$

So

$-x^2+9=2x^2-3\\\Rightarrow 12=3x^2\\\Rightarrow \\\Rightarrow x=\sqrt{\dfrac{12}{3}}\\\Rightarrow x=\pm 2$

$y=-x^2+9=-(2)^2+9\\\Rightarrow y=5$

$y=-(-2)^2+9=5$

So, the points at which the parabola's intersect each other is $(2,5)$ and $(-2,5)$

The three points of the triangle are $(2,5)$ , $(-2,5)$ and $(0,0)$

Area of a triangle is given by

$A=\dfrac{1}{2}[x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2)]\\\Rightarrow A=\dfrac{1}{2}[2(5-0)+(-2)(0-5)+0(5-5)]\\\Rightarrow A=10\ \text{sq. units}$

Area of the triangle formed is $10\ \text{sq. units}$ .

3 0

3 years ago

Help me with my math please

vlada-n [284]

y=4/3x-9

y=mx+b is the slope-intercept equation. Just plug the numbers into the equation. m=slope & y-int=b

3 0

4 years ago