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Thepotemich [5.8K]
3 years ago
14

The organizers of a fair projected a 25 percent increase in attendance this year over that of last year, but attendance this yea

r actually decreased by 20 percent. What percent of the projected attendance was the actual attendance?
Mathematics
1 answer:
Gnom [1K]3 years ago
5 0

Answer: 64 %

Step-by-step explanation:

Assume attendance last year to be equal to "x"

- An increase in percentage sees us add the percentage amount to 100.

- A decrease in percentage sees us subtract the percentage amount from 100.

Projected attendance = ((100+25)/100) * x = 1.25x

Actual attendance = ((100-20)/100) * x = 0.80x

Hence ratio of a actual to projected attendance = 0.80x/1.25x = 0.64

Convert into percentage = 0.64 * 100 = 64 %

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Answer:

What's the question?

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Show me how to get this answer show your work
Rama09 [41]

We know that angle MKJ is comprised of angle MKL and angle LKJ. That means if we add MKL and LKJ, we should get 80 degrees, which is the measure of angle MKJ.

MKL + LKJ= MKJ \implies \\ 2x+10+3x-5=80 \implies \\ 5x+5=80 \implies\\ 5x=75 \implies \\ x=15

So, we know that our x is 15. That is not enough to tell whether KL is an angle bisector, because we have to evaluate both MKL and LKJ with x=15, so:

MKL=2(15)+10 = 40\\ LKJ=3*15-5=40

So we see that these two angles are actually bisectors, and the third question best describes this phenomenon.

6 0
3 years ago
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What is the length of segment CD question mark
blagie [28]

Answer:

CD = two square root of 10 end square root

Step-by-step explanation:

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d = \sqrt{(y_2-y_1)^2 + (x_2-x_1)^2} \\\\d = \sqrt{(-4--2)^2 + (-7--1)^2} \\\\d = \sqrt{-2^2 + -6^2}\\\\d = \sqrt{4 + 36}\\\\d=\sqrt {40} = 2\sqrt{10}

8 0
3 years ago
The area of a rectangle is the rectangle’s length times its width. Write a program that asks for the length and width of two rec
Mnenie [13.5K]

Answer:

Using c++

Check the image for colors.

Step-by-step explanation:

#include <iostream>

using namespace std;

int main()

{

   float length1,length2,width1,width2,area1,area2;

   

   cout<<"length of Rectangle 1\n";

   cin>>length1;

   cout<<"\nwidth of Rectangle 1\n";

   cin>>width1;

   cout<<"\nlenght of Rectangle 2\n";

   cin>>length2;

   cout<<"\nwidth of Rectangle 2\n";

   cin>>width2;

   

   area1=length1*width1;

   area2=length2*width2;

   

   if (area1<area2)

   {cout << "\nRectangle 2 has greater area";}

   else {

               if (area1>area2)

                  {cout << "\nRectangle 1 has greater area";}

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   return 0;

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7 0
3 years ago
9. A contestant on a game show must guess the price of a new car. The contestant will
iren [92.7K]

Given :

A contestant on a game show must guess the price of a new car. The contestant will  win if his guess is within $1000 of the price of the car.

To Find :

If the price of the car is  $24,995 and the contestant's guess is represented by g, what absolute value  inequality represents this situation.

Solution :

Let, range in which participant guess would be considered correct is r.

So, r should be in range $( 24,995 ± 1000 ).

( 24,995 - 1000 ) ≤ r ≤ ( 24,995 + 1000 )

23,995 ≤ r ≤ 25,995

Therefore, the correct inequality is 23,995 ≤ r ≤ 25,995 .

Hence, this is the required solution.

4 0
3 years ago
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