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3 years ago

can you also use the LCM of the denominator of the fractions to rewrite the difference 8/15-1/6?what is the difference?

1 answer:

8 0

So to add or subtract fractions, the bottom number must be the same

so we need to make the bottom numbers the same without changing the fraction itself

exg to change 1/4 to 4/16 you multiply 1/4 by 4/4 (which equals 1) to get 4/16

so we need to find the Least Common Multiple or the smallest number that each can multiply into so

first we find the factors
15=3 times 5
6=2 times 3

we find the numbers in both of them
there is one 2, one 3, and one 5 so 2 times 3 times 5 or 30

the LCM=30

8/15 times 2/2 (or 1)=16/30
1/6 times 5/5 (or 1)=5/30
16/30-6/30=(16-5)/30=11/30

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Which of the following is a correct equation for the line passing through the point (-2,1) and having slope m= 1/2?

Taya2010 [7]

Incomplete Question the complete Qs is

Which of the following is a correct equation for the line passing through the point (-2,1) and having slope m = 1/2?

a: y=1/2x+2

b: y=-2x+1/2

c: x-2y=-4

d: y-1=1/2(x+2)

Answer:

The Correct option is c. x-2y=-4

Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is

$x-2y=-4$

Step-by-step explanation:

Given:

$Slope = m =\dfrac{1}{2}$

point A(x₁, y₁)=(-2,1)

To Find:

Equation of Line =?

Solution:

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,

i.e equation in point - slope form

$(y-y_{1})=m(x-x_{1})$

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2 , 1) we get

$(y-1)=\dfrac{1}{2}(x-(-2))\\\\2y-2=x+2\\x-2y=-2-2=-4\\x-2y=-4$ As required

Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is

$x-2y=-4$

6 0

3 years ago

If the base of a square pyramid is 9 centimeters, and it has a volume of 324 cubic centimeters, what is the height of the pyrami

masha68 [24]

The volume (V) of a pyramid is found using the formula

V = $\frac{1}{3}$ × area of base × height(h)

area of base = 9² = 81 ← area of a square, hence

324 = $\frac{1}{3}$ × 81 × h = 27h ( divide both sides by 27 )

h = $\frac{324}{27}$ = 12 → A

3 0

3 years ago

The ration of girls to boys in a marching band is 10to8 if there are 32 boys in the marching band how many of the students in th

daser333 [38]

Answer:

40 girls

Step-by-step explanation:

if there r 32 than u know 8 times 4 equals 32. Then u have to multiply 4 on the other side as well. So 10 times 4 equals 40 girls

5 0

3 years ago

The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

4 0

3 years ago

(9 • 27)^1/2<br> A.) 9<br> B.)3radical3<br> C.) 9radical3<br> D.)27

kobusy [5.1K]

$(9 \times 27)^ \frac{1}{2} = \sqrt{9 \times 27} = \sqrt{9 \times 3 \times 9} = 9 \sqrt{3}$

Answer: 9√3

6 0

4 years ago