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Snezhnost [94]
3 years ago
12

The model of a trinomial is shown. What are the factors of the trinomial? Check all that apply. X – 14 x + 7 x – 7 x – 2 x + 2 x

+ 14
Mathematics
2 answers:
Readme [11.4K]3 years ago
7 0

Answer:

x-7 and x+2

Step-by-step explanation:

tatyana61 [14]3 years ago
3 0

Answer:

-13x + 14

Step-by-step explanation:

Many of the terms cancel out (ex: + 7x and -7x, -2x and +2x)

So, with those omitted, you are left with:

-13x + 14

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to make lemonade , bart poured 3 gallons of water into a large container . he added 1 gallon of lemon juice. how many quarts of
pentagon [3]

Answer:16quarts

Step-by-step explanation:

4 times 4 is 16 because 4 quarts is one gallon

5 0
3 years ago
5(-1x+5)=10 pls help
Leya [2.2K]

Answer:

-5x+5=10

-5x=10-5

-5x=5

x=-5/5

x=-1

7 0
3 years ago
Read 2 more answers
Two factory plants are making TV panels. Yesterday, Plant A produced 7000 fewer panels than Plant B did. Four percent of the pan
amid [387]

Step-by-step explanation:

17000

Let the number of panels Plant B produced be x.

7000(0.04)+0.02x=620 \\ \\ 0.02x=340 \\ \\ x=17000

8 0
2 years ago
Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

if e<b, then eˣ<bˣ<bˣln(b) ( f(x)<f'(x) )

but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
4 years ago
Prove that if one solution for a quadratic equation of theform x2 + bx + c = 0 is rational (where b and c are rational),then the
Elenna [48]

Answer:

The other solution of the given equation x² + bx + c = 0   is also rational number.

Step-by-step explanation:

Here, given: ax² + bx + c = 0 is a quadratic equation

Also, one solution  (r)  of equation is RATIONAL.

To show: The other solution (s)  is also RATIONAL

Now, here: as x² + bx + c = 0

Since r and s are the two given solutions, the given equation can be factorized as:

x² + bx + c =  (x -r) (x - s)

Simplifying LHS, we get:

(x -r) (x - s) = x x - r (x) - s (x) +  (r)(s)

                 =  x² + x(-r - s) +  rs

or, x² + bx + c = x² + x(-r - s) +  rs

Comparing the related terms, we get:

b =  (-r - s)    

⇒  b +  s = - r

or, s  = -r - b

Now, given : r = Rational  and the negative of a rational is also rational.

⇒  -r is also rational

Also, difference of two rational number is also rational.

⇒ -r - b is also rational

⇒ s is a RATIONAL NUMBER

Hence, the other solution of the given equation x² + bx + c = 0   is also rational number.

7 0
4 years ago
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