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3 years ago

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Which quotient is the same as the quotient 6.93÷0.4? Is it 693÷4 or 69.3÷4 or 69.3÷40 or 693÷0.004?

2 answers:

7nadin3 [17]3 years ago

6 0

The answer will be 69.3÷4. Hope it help!

Klio2033 [76]3 years ago

3 0

Answer:

Which quotient is the same as the quotient 6.93÷0.4? Is it 693÷4 or 69.3÷4 or 69.3÷40 or 693÷0.004?

Step-by-step explanation:

Which quotient is the same as the quotient 6.93÷0.4? Is it 693÷4 or 69.3÷4 or 69.3÷40 or 693÷0.004?

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A right circular cylinder has a height of 22 1/4 ft and a diameter 2 2/5 times its height. What is the volume of the cylinder? E

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Answer:

The volume of cylinder is:

49806.06 ft^3

Step-by-step explanation:

We are given a right circular cylinder with:

Height(h)= $22\frac{1}{4}ft=\dfrac{89}{4}ft$

and a diameter is $2\frac{2}{5}$ times it's height.

i.e. $\dfrac{12}{5}$ times it height.

i.e. the diameter is given as:

$\dfrac{12}{5}\times \dfrac{89}{4}=\dfrac{267}{5}ft.$

We know that the radius of cylinder is half the diameter.

Hence, radius(r) of cylinder is:

$\dfrac{1}{2}\times \dfrac{267}{5}\\\\=\dfrac{267}{10}$

The volume(V) of cylinder is given by:

$V=\pi r^2h$

$V=3.14\times (\dfrac{267}{10})^2\times \dfrac{89}{4}\\\\V=\dfrac{19922423.94}{400}\\\\V=49806.06ft^3$

Hence, the volume of cylinder is:

49806.06 ft^3

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Which ordered pair would fall in the first quadrant of the coordinate plane?

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It would be (3,10) because it is much bigger then the others

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12.) When rounding to the nearest 10, what is the largest number that will

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(6-3(cube root of 6)/(cube root of 9)

MatroZZZ [7]

For this case we must simplify the following expression:

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}$

Multiplying the numerator and denominator by $(\sqrt [3] {9}) ^ 2$

$\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =$

We rewrite:

$\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =$

By properties of powers we have that:

$a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =$

We rewrite, moving the exponent within the radical:

$\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {9 ^ 2}} {9} =\\\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {81}} {9} =$

We can rewrite $3 * 3 ^ 3 = 81$

$\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {3 * 3 ^ 3}} {9} =$

We simplify:

$\frac {(6-3 \sqrt [3] {6}) * 3 \sqrt [3] {3}} {9} =$

We apply distributive property:

$\frac {18 \sqrt [3] {3} -9 \sqrt [3] {18}} {9} =$

Simplifying we finally have:

$2 \sqrt [3] {3} - \sqrt [3] {18}$

Answer:

$2 \sqrt [3] {3} - \sqrt [3] {18}$

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Answer:

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Step-by-step explanation:

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