Answer:
Step-by-step explanation:
Comment
There are a number of ways of doing this problem. I don't know which method you are intended to use. One sure way in this case is graphing the equation, I have done this for you. See below. The maximum volume occurs where x = 2
The graph shows that there is a peak at x = 2. That is where the maximum volume is,
Answer
x = 2
Answer:
A. Initially, there were 12 deer.
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. After 15 years, there will be 410 deer.
D. The deer population incresed by 30 specimens.
Step-by-step explanation:

The amount of deer that were initally in the reserve corresponds to the value of N when t=0


A. Initially, there were 12 deer.
B. 
B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.
C. 
C. After 15 years, there will be 410 deer.
D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:
ΔN=N(15)-N(10)
ΔN=410 deer - 380 deer
ΔN= 30 deer.
D. The deer population incresed by 30 specimens.
Answer:
y=x-1
y=-2x-4
although I cant summon a graph for this one, I can give cords
for first graph (-2,-3),(-1,-2),(0,-1), (1,0),(2,1)
For second graph the slope is down 2 over 1, and begins at (0,-4).
(-2,0)(-1,-2),(0,-4),(1,-6),(2,-8)
there is no inverse though
Answer:
10
Step-by-step explanation:
24-14=10
Do these equations backwards to find the answer you are looking for.