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kiruha [24]
3 years ago
6

Please help! will give the crown to whoever helps

Mathematics
1 answer:
andrew11 [14]3 years ago
5 0
DEF is congruent to D’E’F’ because DEF is the same shape and size as D’E’F’
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Can u answer this mathematics question and show your work
Mnenie [13.5K]

See this solution/explanation (answer is '7 meters'):

1. According to the condition 'y' means the height, and 'x' - the length from the start of the lift hill.

2. The phrase 'height of 343 meters' means y=343.

3. From the another side y=x³. If to substitute 343 instead of 'y': 343=x³, - it is possible to find the value of 'x'.

x=<u>7 [m]</u> - how far from the start of the lift hill...

5 0
3 years ago
What is 44 dvided into 2 groups with a ratio of 4/7
zalisa [80]

Total units would be: 4+7 = 11

value of 1 unit = 44/11 = 4

Ratio would be: 4(4) & 7(4) = 16 & 28

4 0
3 years ago
What is the result of a dilation of scale factor 3 centered at the origin of the line 2y + 3x=10?? PLEASE HELP PLEASEEEEEEEEE
maks197457 [2]

Given:

The equation of a line is:

2y+3x=10

The line is dilated by factor 3.

To find:

The result of dilation.

Solution:

The equation of a line is:

2y+3x=10

For x=0,

2y+3(0)=10

2y+0=10

y=\dfrac{10}{2}

y=5

For x=2,

2y+3(2)=10

2y+6=10

2y=10-6

2y=4

Divide both sides by 2.

y=\dfrac{4}{2}

y=2

The given line passes through the two points A(0,5) and B(2,2).

If the line dilated by factor 3 with origin as center of dilation, then

(x,y)\to (3x,3y)

Using this rule, we get

A(0,5)\to A'(3(0),3(5))

A(0,5)\to A'(0,15)

Similarly,

B(2,2)\to B'(3(2),3(2))

B(2,2)\to B'(6,6)

The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-15=\dfrac{6-15}{6-0}(x-0)

y-15=\dfrac{-9}{6}(x)

y-15=\dfrac{-3}{2}x

Multiply both sides by 2.

2(y-15)=-3x

2y-30=-3x

2y+3x=30

Therefore, the equation of the line after the dilation is 2y+3x=30.

3 0
3 years ago
G(x)=1/2(x-3)+1 find the inverse
Marysya12 [62]

g(x)=\dfrac{1}{2}(x-3)+1\\\\y=\dfrac{1}{2}(x-3)+1\\\\\text{replace x with y and y with x}\\\\x=\dfrac{1}{2}(y-3)+1\\\\\text{solve for y}\\\\\dfrac{1}{2}(y-3)+1=x\ \ \ \ |-1\\\\\dfrac{1}{2}(y-3)=x-1\ \ \ \ |\cdot2\\\\y-3=2x-2\ \ \ \ |+3\\\\y=2x+1\\\\Answer:\ \boxed{g^{-1}(x)=2x+1}

4 0
3 years ago
In a word there are 8 letters. Of them c letters are vowels, and the rest are consonants. What part of all the letters of this w
Lera25 [3.4K]

8 = letter

c = vowels

8 -c = consonants

_____________

c = 3

so, you've got three vowels

6 0
3 years ago
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