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3 years ago

8

Help please I need it:

1 answer:

jonny [76]3 years ago

6 0

Answer:

Step-by-step explanation:

The number of sandwiches sold: 73

The cost to make one sandwich: S

The profit the band earns from one sandwich: 0.2S

The amount of money that the band recieves for selling one sandwich:

S + 0.2S

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Melons cost $20 pet Crate, and apples cost $8 per create. an order comes in for a total of 48 crates for $420. what was the numb

Alika [10]

Answer:

The number of melon was 3 and the number of apples was 45.

Step-by-step explanation:

1. Melons cost $20 per crate and apples cost $8 per create. If the total was 48 crates for $420, you can make the following system of equations, where $x$ is the number of melons and $y$ is the number of apples:

$\left \{ {{x+y=48} \atop {20x+8y=420}} \right.$

2. By applying the Method of substitution, you can solve for $y$ in the first equation and substitute it into the second one to find $x$ . Then, you can substitute the value of $x$ into the first equation to find $y$ :

$y=48-x$

$20x+8(48-x)=420\\20x+384-8x=420\\12x=36\\x=3$

$3+y=48\\y=45$

4 0

3 years ago

A company claims that its packages of beads contain, on average, 50 beads with a standard deviation of 5.4 beads. In a hypothesi

Sergio039 [100]

Answer:

The answer is 2.07

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

4. Find an equation for each line.

DedPeter [7]

Answer:

1 lap in 8/10 (4/5) of a minute

Answer is B, 8/10 minute!

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Step-by-step explanation:

3 0

3 years ago

If (ax+2)(bx+7)=15x2+cx+14 for all values of x, and a+b=8, what are the 2 possible values fo c

dolphi86 [110]

Given:

$(ax+2)(bx+7)=15x^2+cx+14$

And

$a+b=8$

Required:

To find the two possible values of c.

Explanation:

Consider

$\begin{gathered} (ax+2)(bx+7)=15x^2+cx+14 \\ abx^2+7ax+2bx+14=15x^2+cx+14 \end{gathered}$

So

$\begin{gathered} ab=15-----(1) \\ 7a+2b=c \end{gathered}$

And also given

$a+b=8---(2)$

Now from (1) and (2), we get

$\begin{gathered} a+\frac{15}{a}=8 \\ \\ a^2+15=8a \\ \\ a^2-8a+15=0 \end{gathered}$ $a=3,5$

Now put a in (1) we get

$\begin{gathered} (3)b=15 \\ b=\frac{15}{3} \\ b=5 \\ OR \\ b=\frac{15}{5} \\ b=3 \end{gathered}$

We can interpret that either of a or b are equal to 3 or 5.

When a=3 and b=5, we have

$\begin{gathered} c=7(3)+2(5) \\ =21+10 \\ =31 \end{gathered}$

When a=5 and b=3, we have

$\begin{gathered} c=7(5)+2(3) \\ =35+6 \\ =41 \end{gathered}$

Final Answer:

The option D is correct.

31 and 41

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1 year ago

Constant rate of change help!

Nadusha1986 [10]

All I know is the first one is -0.8 ft/min

6 0

3 years ago