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1 year ago

How to determine the direction a parabola opens

Mathematics

1 answer:

kozerog [31]1 year ago

5 0

Answer:

Upward or Downward

Step-by-step explanation:

A parabola is the graph of a quadratic function y = ax2 + bx + c. The graphs below depict two typical parabolas:

For clarity, we indicate their x-intercepts with red dots, their y-intercepts with pink dots, and the vertex of each parabola with a green dot:

The first parabola (a U shape) opens vertically, whereas the second parabola opens downwards (is an upside down U shape).

Given the function y = ax2 + bx + c, write the following:

<em>If an is greater than zero (positive), the parabola widens upward.</em>
<em>If the value is 0 (negative), the parabola expands downward.</em>

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lutik1710 [3]

Answer:

15%

Step-by-step explanation:

300 / 3 = 100

45 / 3 = 15

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sveticcg [70]

<h2>>>> Answer <<<</h2>

Let's check which polynomial is divisible by ( x - 1 ) using hit , trial and error method .

A ( x ) = 3x³ + 2x² - x

The word " divisible " itself says that " it is a factor "

Using factor theorem ;

Let;

=> x - 1 = 0

=> x = 1

Substitute the value of x in p ( x )

p ( 1 ) =

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3 ( 1 ) + 2 ( 1 ) - 1

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This implies ;

A ( x ) is not divisible by ( x - 1 )

Similarly,

B ( x ) = 5x³ - 4x² - x

B ( 1 ) =

5 ( 1 )³ - 4 ( 1 )² - 1

5 ( 1 ) - 4 ( 1 ) - 1

5 - 4 - 1

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This implies ;

B ( x ) is divisible by ( x - 1 )

Similarly,

C ( x ) = 2x³ - 3x² + 2x - 1

C ( 1 ) =

2 ( 1 )³ - 3 ( 1 )² + 2 ( 1 ) - 1

2 ( 1 ) - 3 ( 1 ) + 2 - 1

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This implies ;

C ( x ) is divisible by ( x - 1 )

Similarly,

D ( x ) = x³ + 2x² + 3x + 2

D ( 1 ) =

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This implies ;

D ( x ) is not divisible by ( x - 1 )

<h2>Therefore ; </h2>

<h3>B ( x ) & C ( x ) are divisible by ( x - 1 ) </h3>

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Leya [2.2K]

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Evgesh-ka [11]

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