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stealth61 [152]
3 years ago
12

Drake wants to save $750 so that he can take a class on computer analysis for cars. The class is being held on various dates ove

r the next several months. Drake is planning to take the class 6 weeks from now, so he plans to save $125 each week. Unfortunately, Drake had to take out a little money from his savings in the 3rd week. After 4 weeks, Drake has $470. He knows that he must adjust his plan in order to meet his goal. Drake came up with the following options: Option A: Stay with saving the original amount each week but take the class a week later than originally planned. Option B: Increase the amount of money he saves each week by $15 from his original plan. Which of the following is a true statement? a. Only option A will allow him to meet his goal. b. Only option B will allow him to meet his goal. c. Both options A and B will allow him to meet his goal. d. Neither option A nor option B will allow him to meet his goal.
Mathematics
1 answer:
STatiana [176]3 years ago
8 0
C. Both options A and B will allow him to meet his goal.



Looking at Drake's situation after 4 weeks, he only has $470 saved. By his original plan, he should have had $500 saved. So he's $30 short of his goal and has 2 weeks until his originally planned class. If he goes with option A and takes the later class, he will save an additional $125 which is more than enough to make up the $30 short fall. So option A will work for him to save enough money for his class. With option B, he will save $140 for the last 2 weeks of his plan giving him a savings of $280 for the last 2 weeks. Adding the $470 he's already saved will give him a total savings of $470 + $280 = $750 which is enough for him to attend his class. So option B will also allow Drake to attend his desired class. Both options A and B allow him to meet his goal. Hence, the answer is "c".
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Let n1equals50​, Upper X 1equals30​, n2equals50​, and Upper X 2equals10. Complete parts​ (a) and​ (b) below. a. At the 0.05 leve
Viefleur [7K]

Answer:

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.

Step-by-step explanation:

1) Data given and notation  

X_{1}=30 represent the number of people with a characteristic in 1

X_{2}=10 represent the number of people with a characteristic in 2

n_{1}=50 sample of 1 selected  

n_{2}=50 sample of 2 selected  

p_{1}=\frac{30}{50}=0.6 represent the proportion of people with a characteristic in 1

p_{2}=\frac{10}{50}=0.2 represent the proportion of people with a characteristic in 2

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportion 1 is different from proportion 2 , the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{30+10}{50+50}=0.4  

3) Calculate the statistic  

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.6-0.2}{\sqrt{0.4(1-0.4)(\frac{1}{50}+\frac{1}{50})}}=4.082    

4) Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.    

Since is a two sided test the p value would be:  

p_v =2*P(Z>4.082)=4.46x10^{-5}  

So the p value is a very low value and using any significance level for example \alpha=0.05 always p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say the the proportion 1 is significantly different from proportion 2.  

3 0
3 years ago
A research organization keeps track of what citizens think is the most important problem facing the country today. They randomly
Nuetrik [128]

Answer:

Step-by-step explanation:

From the information given, the population is divided into sub groups. Each group would consist of citizens picking a particular choice as the most important problem facing the country. The choices are the different categories. In this case, the null hypothesis would state that the distribution of proportions for all categories is the same in each population. The alternative hypothesis would state that the distributions is different. Therefore, the correct test to use to determine if the distribution of​ "problem facing this country ​today" is different between the two different​ years is

A) Use a​ chi-square test of homogeneity.

8 0
3 years ago
PLEASEEEE ANSWER ASAP
Alona [7]

Answer:

x = -1, x = 1

Step-by-step explanation:

Factor the equation. (It's a difference of squares, so we know the form will be (a-b)(a+b).)

y = x^{2} - 1\\y = (x-1)(x+1)

Test this by FOILing it out, if you're unsure. This is something it can be good to memorize!

Set it equal to 0.

0 = (x+1)(x-1)

Separate the two parenthetical expressions by the Zero Product Property.

0 = x+1\\0 = x-1

Solve for x!

x=-1, x=1

3 0
3 years ago
What is the least common denominator of 5/6 and 3/4?
ololo11 [35]
This lcd is also twelve
5 0
3 years ago
Find x. problem is in picture
Masja [62]

Answer:

x=21

Step-by-step explanation:

We know that C is a right angle, which means that x + 3x+6 = 90

4x+6=90\\4x=84\\x=21

Have a nice day. hope I helped please rate brainliest!

3 0
3 years ago
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