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stealth61 [152]
3 years ago
12

Drake wants to save $750 so that he can take a class on computer analysis for cars. The class is being held on various dates ove

r the next several months. Drake is planning to take the class 6 weeks from now, so he plans to save $125 each week. Unfortunately, Drake had to take out a little money from his savings in the 3rd week. After 4 weeks, Drake has $470. He knows that he must adjust his plan in order to meet his goal. Drake came up with the following options: Option A: Stay with saving the original amount each week but take the class a week later than originally planned. Option B: Increase the amount of money he saves each week by $15 from his original plan. Which of the following is a true statement? a. Only option A will allow him to meet his goal. b. Only option B will allow him to meet his goal. c. Both options A and B will allow him to meet his goal. d. Neither option A nor option B will allow him to meet his goal.
Mathematics
1 answer:
STatiana [176]3 years ago
8 0
C. Both options A and B will allow him to meet his goal.



Looking at Drake's situation after 4 weeks, he only has $470 saved. By his original plan, he should have had $500 saved. So he's $30 short of his goal and has 2 weeks until his originally planned class. If he goes with option A and takes the later class, he will save an additional $125 which is more than enough to make up the $30 short fall. So option A will work for him to save enough money for his class. With option B, he will save $140 for the last 2 weeks of his plan giving him a savings of $280 for the last 2 weeks. Adding the $470 he's already saved will give him a total savings of $470 + $280 = $750 which is enough for him to attend his class. So option B will also allow Drake to attend his desired class. Both options A and B allow him to meet his goal. Hence, the answer is "c".
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a/sinA = b/sinB = c/sinC

This states that the length of a side, divided by the sine of the opposite angle, is the same for every side in a triangle.

2.) We must solve for side x in the smaller triangle. We know two sides of the large triangle, and one side of the smaller triangle. The two parallel lines tell us that angle A = angle N and angle B = angle P. The side of the smaller triangle that we do know is, 67.2 - 32 = 35.2 m. Now we can plug values into the law of sines.

35.2/sinB = x/sinA
sinA = (x/35.2)sinB

81.9/sinB = 67.2/sinA
sinA = (67.2/81.9)sinB

We can now equate both sinA equations and solve for x.

(x/35.2)sinB = (67.2/81.9)sinB
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3.) We will make the assumption that the angle divided by the line inside the triangle is split in equal halves, therefore, both angles are the same. The angles at point D are angle D and and 180-D. It turns out that sinD = sin(180-D). If you do not believe this principle, test it out in a calculator. This will simplify our problems. We can simply use the law of sines once more.

(x+4)/sinE = 44.8/sinD
sinE = ((x+4)/44.8)sinD

35/sinE = 56/sinD
sinE = (35/56)sinD

((x+4)/44.8)sinD = (35/56)sinD
(x+4)/44.8 = 35/56
x+4 = (35/56)(44.8)
x = (35/56)(44.8) - 4
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(5/3)sinθₓ = ((45/(13+2x))sinθₓ
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5.) The area of a triangle is found using the formula, A = (1/2)b·h. We are already given the area of the triangle and the height of the triangle. The base of this triangle IS the hypotenuse, so solving for the base will answer this question.

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