How far do you need to continue the division of 1 by 7 to know the answer?

Mathematics

1 answer:

sergejj [24]3 years ago

7 0

Answer:

Step-by-step explanation:

upto 7digits after decimals

1/7 = 0.1428571

1/7 is a non terminating repeating rational number. .142857 is set that repeats again

You might be interested in

Write the time 8:30 then write this time in two other ways using words

guajiro [1.7K]

Half past eight or thirty minutes to nine

8 0

3 years ago

The balance of a loan is $2,570 in January, and the monthly payment is $125.50. The relationship between the loan balance, y, an

Hoochie [10]

1600<2570-125.5x<2000 subtract 2570 from all terms...

-970<-125.5x<-570 divide all terms by -125.5 (and reverse signs because of division by a negative!)

7.73>x>4.54 and x is months since January, and since months can only be integers...

x=[5,7]

So January + 5, 6, and 7 respectively are the three months that satisfy the equation...

June, July, and August.

4 0

3 years ago

Read 2 more answers

9th grade Algebra 1 help??

andriy [413]

3 eggs for brownies, 2 eggs for cookies.

Because the total count went up 2 for one more batch of cookies, you know that 1C(ookies) = 2 eggs
3C = 6 eggs
15 - 6 = 9 eggs
3B(rownies) = 9 eggs
1B = 3 eggs

8 0

3 years ago

Johnson Chemicals is considering two options for its supplier portfolio. Option 1 uses two local suppliers. Each has a "unique-e

sashaice [31]

Answer:

a) P=0.0175

b) P=0.0189

Step-by-step explanation:

For both options we have to take into account that not only the chance of a "superevent" will disable both suppliers.

The other situation that will disable both is that both suppliers have their "unique-event" at the same time.

As they are, by definition, two independent events, we can calculate the probability of having both events at the same time as the product of both individual probabilities.

a) Then, the probability that both suppliers will be disrupted using option 1 is

$P_1=P_{se}+P_{ue}^2=0.015+(0.05)^2=0.015+0.0025=0.0175$