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Olegator [25]
3 years ago
15

4/y+2 - 9/y-2 = 9/y^2-4

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
8 0
Going off the idea that this is 4/(y+2) - 9/(y-2) = 9/(y^2-4), let's first rewrite y^2-4 in the form of a^2-b^2, where a=y and b=2.
y/(y+2)-9/(y-2)=9/(y^2-2^2)
Now, use difference of squares: a^2-b^2=(a+b)(a-b)
4/(y+2)-9/(y-2)=9/((y+2)(y-2))
Multiply both sides by the Least Common Denominator: (y+2)(y-2)
4(y-2)-9(y+2)=9
Then keep on simplifying until you get your answer
-5y-26=9
-5y=9+26
-5y=35
y=35/-5
y=-7
Yay! Our answer is y=-7!
tangare [24]3 years ago
6 0
The answer y =-7
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we have the function

E=\sin \frac{\pi}{14}t

Part a

For t=7

substitute in the given function

\begin{gathered} E=\sin \frac{\pi}{14}7 \\ E=1 \end{gathered}

For t=14

\begin{gathered} E=\sin \frac{\pi}{14}14 \\ E=0 \end{gathered}

For t=21

\begin{gathered} E=\sin \frac{\pi}{14}21 \\ E=-1 \end{gathered}

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\begin{gathered} E=\sin \frac{\pi}{14}28 \\ E=0 \end{gathered}

For t=35

\begin{gathered} E=\sin \frac{\pi}{14}35 \\ E=1 \end{gathered}

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Part B

Remember that

The Period goes from one peak to the next

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B=pi/14

Period=(2pi)/(pi/14)=2pi*14/pi=28

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1 year ago
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