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2 years ago

4/y+2 - 9/y-2 = 9/y^2-4

2 answers:

8 0

Going off the idea that this is 4/(y+2) - 9/(y-2) = 9/(y^2-4), let's first rewrite y^2-4 in the form of a^2-b^2, where a=y and b=2.
y/(y+2)-9/(y-2)=9/(y^2-2^2)
Now, use difference of squares: a^2-b^2=(a+b)(a-b)
4/(y+2)-9/(y-2)=9/((y+2)(y-2))
Multiply both sides by the Least Common Denominator: (y+2)(y-2)
4(y-2)-9(y+2)=9
Then keep on simplifying until you get your answer
-5y-26=9
-5y=9+26
-5y=35
y=35/-5
y=-7
Yay! Our answer is y=-7!

tangare [24]2 years ago

6 0

The answer y =-7
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kotegsom [21]

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Step-by-step explanation:

Formula to find the sample size is given by :_

$n=(\dfrac{z^*\cdot \sigma}{E})^2$

, where z*= critical value corresponds to confidence level.

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E= Margin of error.

As per given , we have

$\sigma=2.8$

E=1

We know that critical value corresponding to 95% confidence level = z*=1.96

Then, the required sample size would be :

$n=(\dfrac{(1.96)\cdot (2.8)}{1})^2$

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3 0

2 years ago

Samantha deposited $100 in a bank account that has earned 5% interest during th his year. Audrey deposited $50 more than Samanth

Nina [5.8K]

Samantha has $100*1.05=$105, and Audrey has $150*1.04=$156. The difference is $156-$105=$51.

5 0

2 years ago

Charge q is one unit of distance away from the source charge s. Charge p is two times further away. The force exerted between S

finlep [7]

Charge q is 1 unit of distance away from the source charge S. Charge p is two times further away. The force exerted between S and q is _____ the force exerted between S and p

a. 1/2

b. 2 times

c. 1/4

d. 4 times

Answer:

4 times

Step-by-step explanation:

Given the following :

Distance between q and S (r) = 1 unit

Distance between P and S (r) = 2 × 1 unit = 2

According to coliumbs law:

F = Ke(q1q2) /r^2

Where F = electrostatic force, Ke = coloumbs constant

q1,q2 = charges, r = distance between two charges

For q and S :

Fsq = Ke(q1q2) / 1^2

Fsq = Ke(q1q2) - - - - - equation 1

For P and S :

Fsp = Ke(q1q2) / 2^2

Fsp = Ke(q1q2) / 4 - - - - - equation 2

Dibiding equation 1 by equation 2

Fsq/Fsp = Ke(q1q2) / Ke(q1q2)/4

Fsq / Fsp = Ke(q1q2) × 4 / Ke(q1q2)

Fsq / Fsp = 4 / 1

Using cross multiplication

Therefore, Fsq = 4 × Fsp

7 0

2 years ago

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scoray [572]

Answer:

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Step-by-step explanation:

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1 year ago

Hello,..... I will mark you as a brainliest

madam [21]

Answer:

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Step-by-step explanation:

Personally I would write it out, although there surely is a formula for it.

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8 0

2 years ago