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allsm [11]
3 years ago
10

6x3=15+3=18 explain the calculation

Mathematics
2 answers:
jolli1 [7]3 years ago
6 0
6*3=18
15+3=18
18=18

The equation is showing that all of the values are equal.
STALIN [3.7K]3 years ago
5 0
Six multiplied by three equals eighteen. fifteen plus three equals eighteen. and eighteen equals eighteen. therefore the equation is equal, because everything in the equation equals eighteen. Good Luck ;)
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22.5 / 1.5 = 15 blocks
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4. Angelina braided b inches of her hair. Brooke braided 4 less than 1/3 the number of inches Angelina braided.
Marta_Voda [28]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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Gemiola [76]

Answer:

you have to make x-3 and x-7 equal to zero...

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Given the function: f(x) = 2x3 - 3/2x, find f(-4).
Sergeu [11.5K]

Answer:

D) -122

Step-by-step explanation:

Given:

f(x) = 2x^3-\frac{3}2x

We need to find f(-4).

Now by substituting the value of x =-4 in above equation we get;

f(-4)= 2\times(-4)^3-\frac{3}{2}\times(-4)\\

By using PEDMAS we will solve for exponential function first we get;

Now we know that (-4)^3=-64

So we get;

f(-4)= 2\times(-64)-\frac{3}{2}\times(-4)\\

Now using PEDMAS we will solve division.

f(-4)= 2\times(-64)-1.5\times(-4)

Now using PEDMAS we solve multiplication.

f(-4)= -128+6

Finally by subtraction we get;

f(-4)= -122

5 0
3 years ago
PLEASE SOLVE AND CHECK. SHOW COMPLETE SOLUTION
Alex17521 [72]

<u>Solution</u><u>:</u>

\sqrt{4x + 13}  = x + 2

  • First square both sides.

=  > ( \sqrt{4x + 13} ) ^{2}  = (x + 2) ^{2}

  • Now, square root and square gets cancel out in the LHS. And in the RHS, apply the identity: (a + b)² = a² + 2ab + b².

=  > 4x + 13 =  {(x)}^{2}  + 2 \times x \times 2 + (2) ^{2} \\  =  > 4x + 13 =  {x}^{2}   + 4x + 4

  • Now, transpose 4x and 4 to LHS.

=  > 4x - 4x + 13 - 4 =  {x}^{2}  \\

  • Now, do the addition and subtraction.

=  >  {x}^{2}  = 9 \\  =  >  x =  \sqrt{9}  \\  =  > x = ±3

<u>Answer</u><u>:</u>

<u>x </u><u>=</u><u> </u><u>±</u><u> </u><u>3</u>

Hope you could understand.

If you have any query, feel free to ask.

3 0
2 years ago
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