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3 years ago

Which graph represents the solution to the system of inequalities?

Mathematics

1 answer:

zheka24 [161]3 years ago

8 0

Answer:

1st graph on line 2

Step-by-step explanation:

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4= Sx+10/2<br><br> that’s a fraction btw

frozen [14]

Answer:

4= Sx+10/2 simplifies to -s*x-1=0

Step-by-step explanation:

8 0

2 years ago

I don’t know how to do that

Alisiya [41]

Answer:

Step-by-step explanation:

Divide 64 by 8 to get 8. this is 1/8 of the books.

3/8 were non fiction, or 24

1/4 (2/8) were picture books, or 16

5/8 were non fiction or picture books, so ’the rest‘ of the chapter books is 3/8.

3/8 were chapter books, or 24.

add the amount of picture books and chapter books since they are the fictional texts.

16+24=40

subtract the amount of non fictional books from the amount of fictional books to get the sum.

40-24=16

8 0

3 years ago

An employee at a pet shop randomly selects two fishes from a tank where there are 5 guppies, 4 platyfishes, and 3 rasboras. What

siniylev [52]

Answer:

0.6 is the probability

8 0

3 years ago

Read 2 more answers

James did not get the PlayStation that he wanted for his birthday, but instead, he got $80. He decided that he will save the $80

Vika [28.1K]

W=14 that’s because 360-80=280 then you have to divide that by 20. And you get 14 weeks.

6 0

2 years ago

Verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial 4x^3+20x^2+2x-3. Also verify the relationship between the ze

Finger [1]

Solution:

we have been asked to verify that -5, 1/2, and 3/4 are the zeroes of the cubic polynomial $4x^3+20x^2+2x-3$

To verify that whether the given values are zeros or not we will substitute the values in the given Polynomial, if it will returns zero, it mean that value is Zero of the polynomial. But if it return any thing other than zeros it mean that value is not the zero of the polynomial.

Let $f(x)=4x^3+20x^2+2x-3\\\\\text{when x=-5}\\\\f(-5)=4(-5)^3+20(-5)^2+2(-5)-3=-13\\\\\text{when x=}\frac{1}{2}\\$

$f( \frac{1}{2} ) = 4 ( \frac{1}{2} )^3+20(\frac{1}{2})^2+2(\frac{1}{2})-3=\frac{7}{2}\\\\$

$\text{when x=}\frac{3}{4}\\\\$

$f( \frac{3}{4} ) = 4 ( \frac{3}{4} )^3+20(\frac{3}{4})^2+2(\frac{3}{4})-3=\frac{183}{16}\\$

Hence -5, 1/2, and 3/4 are not the zeroes of the given Polynomial.

Since sum of roots $=\frac{-b}{a}= \frac{-20}{4}=-5\\$

But $-5+\frac{1}{2}+\frac{3}{4}= \frac{-15}{4}\neq-5$

Hence we do not find any relation between the coefficients and zeros.

Anyway if the given values doesn't represents the zeros then those given values will not have any relation with the coefficients of the p[polynomial.

6 0

3 years ago