I can do like 42, my highest was 54 though
Answer:
1. Use the Adjacent and opposite side (Ignore the Hypotenuse)
Or use HERO'S FORMULA based on the information given
2. Area = 216cm^2
Step-by-step explanation:
There are three to four ways we can go about finding the area of a triangle. And a these would be dependent on the information given about the triangle.
From the question, you said the three side lengths are given. In such case, we employ the HERO FORMULA.
HERO FORMULA:
Area = √ s(s-a)(s-b)(s-c)
where s = 1/2(a + b + c)
a, b, c are the three sides
But since the question insisted that we use 1/2* base * height. Let's use our know of right angle to dissolve that.
A right angle triangle has three sides. The longest is always the Hypotenuse.
Let's take it this way.
Hypotenuse = 30cm
Opposite= 18cm
Adjacent = 24cm
Area = 1/2 * base * height
Area = 1/2 * 18 * 24
Area = 1/2 * 432
Area = 216cm^2
We ignored the longest side, (the Hypotenuse)
Answer:
between x=-1.5 and x = 0
between x = 0 and x = 1.5
Step-by-step explanation:
For the interval -1.5 < x < 1.5, we can see that the slope is negative (i.e from top left to bottom right). Hence it can be said that the graph is decreasing during this interval.
For the other parts of the graph (as shown) the slope is positive (i.e from bottom left to top right). in those areas, the graph is increasing.
Answer:
Dimensions of the poster
Width 29.10 cm
Height 38.80 cm
A(min) = 1129.08 cm²
Step-by-step explanation:
Printed area = 390 cm² = Ap
Lets call x and y dimensions of printed area
x width
y height
Then Ap = x*y and
y = Ap/x ⇒ y = 390/x
Then total area of the poster is:
A(t) = ( x + 12 ) * ( y + 16 ) and y = 390/x
A as a function of x
A(x) = ( x + 12 ) * ( 390/x + 16 ) ⇒ A(x) = 390 + 16x + 4680/x + 192
A(x) = 582 + 16x + 4680/x (1)
Taking derivatives
A´(x) = 16 - (4680/x²) ⇒ A´(x) = 0
[ 16x² -4680] /x² = 0 16x²- 4680 = 0 ⇒ x² = 4680/16
x = 17.10 cm and y = 390/x y = 390/17.10 y = 22.80 cm
A(t) = ( 17.10 + 12 ) * ( 22.80 + 16 )
A(t) = 29.10 * 38.80
A(t) = 1129.08 cm²
If we substitute in equation (1) the value of x ( 17.10) we see A(x) > 0
Then there is a minimun at the point x = 17.10
Rounded to the near test thousandth: 6.709
