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3 years ago

What is the slope-intercept form of the equation of the line with the slope of -5/8 that passes through the point (-14,6)

Mathematics

1 answer:

inessss [21]3 years ago

5 0

Step-by-step explanation:

y-y1 = m(x-x1) is the equation for a linear line in y=mx+b (slope intercept)

slope = m = -5/8

x1 = -14

y1 = 6

y-6 = -5/8 (x--14)

y-6 = -5/8 (x+14)

y-6 = -5/8x-70/8

y-48/8= -5/8x-70/8

y = -5/8x - 22/8

When x = 0, y = -22/8, which makes (0, -22/8) your y intercept

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2 years ago

The ratio of sweaters to dresses that Jennifer has is 8:5. If

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3 years ago

A pumpkin is launched directly upwards at 72 feet per second from a platform 24 feet high. The pumpkins height, h, at time t sec

STALIN [3.7K]

Answer: Maximum height = 105 feet

And, It takes 9/4 seconds to reach that point.

Step-by-step explanation:

Here the given function that shows the height of the pumpkin,

$h(t) = -16t^2 + 72t + 24$ --------(1)

Where t is the time in second.

Differentiating equation (1) with respect to t,

We get, $h'(t) = -32 t + 72$

Again differentiating above equation with respect to t,

We get, $h''(t) = -32$

For maximum or minimum, $h'(t) = 0$

$- 32 t + 72 = 0$

$32 t = 72$

$t = \frac{9}{4}$

At t = 9/4 , h''(t) = Negative value,

Therefore, At t = 9/4 seconds, h(t) is maximum,

And, the maximum value is,

$h(\frac{9}{4} ) = -16(\frac{9}{4})^2 + 72(\frac{9}{4}) + 24$

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Therefore, the maximum height of the pumpkin is 105 feet at 9/4 seconds

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3 years ago