How do you find the lateral area of a pentagonal prism?

Answer the following questions:

timama [110]

Answer:

Question 1: 76 dollars. ($76)

2. 1/5

3. 1/19

4. 1/5

Step-by-step explanation:

QUESTION 1:

228 (the amount Mrs. Nicci had) divided by 3 (children) is equal to 76

228/3 = 76

QUESTIONS 2, 3, AND 4.

2. Find the greatest common divisor (GCD). the GCD of 14 and 70 is 14. Then, divide the numerator and denominator by 14.

14/14 = 1

70/14 = 5

WHICH EQUALS 1/5!!

3. Find the greatest common divisor (GCD). the GCD of 5 and 95 is 5. Divide both the numerator and denominator by 5.

5/5= 1

95/5= 19

WHICH EQUALS 1/19!!

4. Find the greatest common divisor (GCD). the GCD of 12 and 60 is 12. So (like we have been doing for the whole part of this question), divide both the numerator and denominator by 12, which is the GCD.

12/12 = 1

60/12 = 5

WHICH EQUALS 1/5!!

Hope this helped.. I think this is like one of the longest Brainly answers I've recently had to type lol

4 0

2 years ago

Two containers designed to hold water are side by side, both in the shape of a

Arisa [49]

Answer:1564cm cube

Step-by-step explanation: v= $\pi$ r2h

v=22/7*6*6*14=1564.containter b volume of water is the total volume in container a so you just have to find container a volume

3 0

2 years ago

Read 2 more answers

Determine what shape is formed for the given coordinates for ABCD, and then find the perimeter and area as an exact value and ro

Helga [31]

Answer:

Part 1) The shape is a trapezoid

Part 2) The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

Part 3) The area is $937.5\ units^2$

Step-by-step explanation:

step 1

Plot the figure to better understand the problem

we have

A(-28,2),B(-21,-22),C(27,-8),D(-4,9)

using a graphing tool

The shape is a trapezoid

see the attached figure

step 2

Find the perimeter

we know that

The perimeter of the trapezoid is equal to

$P=AB+BC+CD+AD$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

we have

A(-28,2),B(-21,-22)

substitute in the formula

$d=\sqrt{(-22-2)^{2}+(-21+28)^{2}}$

$d=\sqrt{(-24)^{2}+(7)^{2}}$

$d=\sqrt{625}$

$d_A_B=25\ units$

Find the distance BC

we have

B(-21,-22),C(27,-8)

substitute in the formula

$d=\sqrt{(-8+22)^{2}+(27+21)^{2}}$

$d=\sqrt{(14)^{2}+(48)^{2}}$

$d=\sqrt{2,500}$

$d_B_C=50\ units$

Find the distance CD

we have

C(27,-8),D(-4,9)

substitute in the formula

$d=\sqrt{(9+8)^{2}+(-4-27)^{2}}$

$d=\sqrt{(17)^{2}+(-31)^{2}}$

$d=\sqrt{1,250}$

$d_C_D=25\sqrt{2}\ units$

Find the distance AD

we have

A(-28,2),D(-4,9)

substitute in the formula

$d=\sqrt{(9-2)^{2}+(-4+28)^{2}}$

$d=\sqrt{(7)^{2}+(24)^{2}}$

$d=\sqrt{625}$

$d_A_D=25\ units$

Find the perimeter

$P=25+50+25\sqrt{2}+25$

$P=(100+25\sqrt{2})\ units$

simplify

$P=25(4+\sqrt{2})\ units$ ----> exact value

$P=135.4\ units$

therefore

The perimeter is $25(4+\sqrt{2})\ units$ or approximately $135.4\ units$

step 3

Find the area

The area of trapezoid is equal to

$A=\frac{1}{2}[BC+AD]AB$

substitute the given values

$A=\frac{1}{2}[50+25]25=937.5\ units^2$

4 0

3 years ago

PLZ ANYONE help me PLZHELP ME ITS DUE RIGHT NOW

Effectus [21]

AH and GB are congruent

4 0

2 years ago

Read 2 more answers

Help me with this question pls pls pls

34kurt

Answer:

Check pdf

Step-by-step explanation:

Download pdf

6 0

2 years ago