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gizmo_the_mogwai [7]
3 years ago
14

What it the explicit formula for 8

Mathematics
1 answer:
Alex3 years ago
3 0

Answer:

-8

Step-by-step explanation:

THANKS

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mash [69]

Answer:

I know what you're asking you are asking to find the least common multiple. However all I can find is the GCF which is 1

Step-by-step explanation:

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Drag the tiles to the correct boxes to complete the pairs. Match each expression with its simplified form. Tiles 3a5 − (-a5) 6a7
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3a^5 - (-a^5) = 3a^5 + a^5 = 4a^5

6a^7 - 2a^7 = 4a^7

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7a^7 - 8a^7 = -a^7
7 0
3 years ago
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A pair of jeans sells for $49.99. The sales tax rate is 6.5%. What is the total cost for the jeans including sales tax?​ Please
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Step-by-step explanation:

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3 years ago
A card is chosen from a standard deck of cards. What is the probability that the card is a club, given that the card is black?
leonid [27]
From a standard deck of cards, one card is drawn. What is the probability that the card is black and a jack? P(Black and Jack) P(Black) = 26/52 or ½ , P(Jack) is 4/52 or 1/13 so P(Black and Jack) = ½ * 1/13 = 1/26 A standard deck of cards is shuffled and one card is drawn. Find the probability that the card is a queen or an ace. P(Q or A) = P(Q) = 4/52 or 1/13 + P(A) = 4/52 or 1/13 = 1/13 + 1/13 = 2/13 WITHOUT REPLACEMENT: If you draw two cards from the deck without replacement, what is the probability that they will both be aces? P(AA) = (4/52)(3/51) = 1/221. 1 WITHOUT REPLACEMENT: What is the probability that the second card will be an ace if the first card is a king? P(A|K) = 4/51 since there are four aces in the deck but only 51 cards left after the king has been removed. WITH REPLACEMENT: Find the probability of drawing three queens in a row, with replacement. We pick a card, write down what it is, then put it back in the deck and draw again. To find the P(QQQ), we find the probability of drawing the first queen which is 4/52. The probability of drawing the second queen is also 4/52 and the third is 4/52. We multiply these three individual probabilities together to get P(QQQ) = P(Q)P(Q)P(Q) = (4/52)(4/52)(4/52) = .00004 which is very small but not impossible. Probability of getting a royal flush = P(10 and Jack and Queen and King and Ace of the same suit) What's the probability of being dealt a royal flush in a five card hand from a standard deck of cards? (Note: A royal flush is a 10, Jack, Queen, King, and Ace of the same suit. A standard deck has 4 suits, each with 13 distinct cards, including these five above.) (NB: The order in which the cards are dealt is unimportant, and you keep each card as it is dealt -- it's not returned to the deck.) The probability of drawing any card which could fit into some royal flush is 5/13. Once that card is taken from the pack, there are 4 possible cards which are useful for making a royal flush with that first card, and there are 51 cards left in the pack. therefore the probability of drawing a useful second card (given that the first one was useful) is 4/51. By similar logic you can calculate the probabilities of drawing useful cards for the other three. The probability of the royal flush is therefore the product of these numbers, or 5/13 * 4/51 * 3/50 * 2/49 * 1/48 = .00000154
5 0
3 years ago
Read 2 more answers
If x &lt; 5 and x &gt;c, give a value of c such that there
Ierofanga [76]

Answer:

c = 6

Step-by-step explanation:

The compound inequality is c < x < 5

If we want a value of c such that there are no solutions, we need to make that inequality false.

From the inequality we can see that 5 must be greater than c to be true.

Therefore, we need to choose a value smaller or equal than 5.

For example, c=6.

If c = 6, that means that x is greater than 6 and smaller than 5. That's impossible, there is no number that meets that.

Therefore, our compound inequality 6 < x < 5 has no solutions.

3 0
3 years ago
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