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agasfer [191]
3 years ago
9

What is the correct name of the polygon below

Mathematics
2 answers:
Zigmanuir [339]3 years ago
7 0
Since it has 8 sides, it is an octagon.
This table will help
<span><span><span>triangle (or trigon)--</span>3
</span><span><span>quadrilateral (or tetragon)--</span>4<span>
</span></span><span>pentagon--5
</span><span>hexagon--6
</span><span>heptagon--7<span>
</span></span><span>octagon--8
</span><span><span>nonagon (or enneagon)--</span>9
</span><span>decagon--10
</span><span><span>hendecagon (or undecagon)--</span>11
</span><span><span>dodecagon (or duodecagon)--</span>12
</span><span><span>tridecagon (or triskaidecagon)--</span>13
</span><span><span>tetradecagon (or tetrakaidecagon)--</span>14
</span><span><span>pentadecagon (or pentakaidecagon)--</span>15
</span><span><span>hexadecagon (or hexakaidecagon)--</span>16
</span><span><span>heptadecagon (or heptakaidecagon)--</span>17
</span><span><span>octadecagon (or octakaidecagon)--</span>18
</span><span><span>enneadecagon (or enneakaidecagon)--</span>19
</span><span>icosagon--20
</span><span><span>icositetragon (or icosikaitetragon)--</span>24
</span><span>triacontagon--30
</span><span><span>tetracontagon (or tessaracontagon)--</span>40
</span><span><span>pentacontagon (or pentecontagon)--</span>50.
</span></span>Please mark me as brainliest. Thanks!!
babunello [35]3 years ago
5 0
Octagon...it has 8 sides
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Wendy has taken two tests with scores of 77 and 80. To get an 82
tiny-mole [99]

Answer:

89

Step-by-step explanation:

Given that Wendy took 2 tests and scored, 77 and 80 respectively, let x represent the grade of Wendy's third test.

To get an average grade of 82, let's generate an equation to find x (Wendy's grade on her third test).

Average grade = sum of all 3 grades all over 3

82 = \frac{77 + 80 + x}{3}

82 = \frac{157 + x}{3}

Multiply 3 by both sides

82*3 = \frac{157 + x}{3}*3

246 = 157 + x

Subtract 157 from each side of the equation

246 - 157 = 157 + x - 157

89 = x

Wendy must score 89 on her third test to have an average of 82.

3 0
3 years ago
Hayley is filling small cone-shaped cups with clay for an art project. Each cup has a height of 4 centimeters and a diameter of
Ierofanga [76]

Answer:

10.6 cones

Step-by-step explanation:

Given data

h= 4cm

d= 1.5cm

r= d/2= 0.75cm

The expression for the volume of a cone is

V= 1/3πr^2h

substitute

V= 1/3*3.142*(0.75)^2*4

V=  1/3*3.142*2.25

V=1/3*7.0695

V= 2.3565cm^3

Since the volume of 1 cone is 2.4cm^3

She can fill

=25/2.3565

=10.6 cones

About 10.6 cones

8 0
2 years ago
5. Give the domain and range for this
skad [1K]

Answer:

d={1,-1,2,-2,4,-3,3}

r={1,4,9}

8 0
3 years ago
Focus on number two ok
melomori [17]
Its simple, convert 1 and 2/3 into a fraction which is 5/3 and use KCF which is Keep Change and Flip,

How this works is that you keep the first fraction, then change the division sign to a multiplication sign (Change = change the sign into its oppisite) then flip the other fraction from being 5/3 into 3/5. And then you multiply top times top and bottom times bottom. After that you simplify if you can, Hope this helped!
7 0
2 years ago
Read 2 more answers
9. Complete the reasons in the proof below.
Arada [10]
For a), this is clearly a given as it is literally to the right of where it says “Given:”
For b), since ON bisects ∠JOH, this means that it splits it into two separate angles - JON and HON, which are similar due to that bisects mean that it splits it equally into two halves
For c), since NO is the same thing as NO, it is equal to itself
For d), since AAS (angle-angle-side) congruence states that if there are two angles that are congruent (proved in a) and b) ) as well as that a side is congruent (proved in c) ), two triangles are congruent
For e), since two triangles are congruent, every side must have one side that it matches up to in the other triangle. As the opposite side of angle H is JO and the opposite side of angle J is OH, and ∠J=∠H, those two are congruent. As JN and HN are the two sides left, they must be congruent.

Feel free to ask further questions!
4 0
3 years ago
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