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frosja888 [35]
3 years ago
9

Solve for x Enter the solutions from least to greatest. -4x^2– 7 = -11

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
3 0

Answer:

x = 1, x = -1

Step-by-step explanation:

-4x² = -4

x² = 1

x = \sqrt{1}

x = ±1

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A recipe calls for ⅓ cup of brown sugar for 1 batch. How many batches can be made 1⅔
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3 years ago
Raj’s bathtub is clogged and is draining at a rate of 1.5 gallons of water per minute. The table shows that the amount of water
marysya [2.9K]

The range of y will be all real numbers such that 0≤y≤40

The complete question is:

Raj’s bathtub is clogged and is draining at a rate of 1.5 gallons of water per minute. The table shows that the amount of water remaining in the bathtub, y, is a function of the time in minutes, x, that it has been draining. What is the range of this function? all real numbers such that y ≤ 40 all real numbers such that y ≥ 0 all real numbers such that 0 ≤ y ≤ 40 all real numbers such that 37.75 ≤ y ≤ 40

<h3>What is inequality?</h3>

The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to’, > ‘greater than, or < ‘less than.

Raj’s bathtub is clogged and is draining at a rate of 1.5 gallons of water per minute.

The amount of water remaining in the bathtub = y

The function of  time in minutes, that it has been draining = x

At 0 minutes the amount of water is 40 gallons.

The highest volume of water is 40 which is decreasing at the rate of 1.5 gallons per minute.

The given function is a linear function  

y = 0

However, the volume of water can be 0 but cannot ever be negative.

Therefore the range of y will be all real numbers such that 0≤y≤40

To know more about inequality follow

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#SPJ1

5 0
1 year ago
Solve by using system of equations.
tekilochka [14]

Answer:

(0, 1) and (-1, -3)

Step-by-step explanation:

Given quadratic equations:

\begin{cases}y=2x^2+6x+1\\y=-4x^2+1\end{cases}

Solve by the <u>method of substitution</u> by substituting the first equation into the second equation:

\implies 2x^2+6x+1=-4x^2+1

Add 4x² to both sides:

\implies 2x^2+6x+1+4x^2=-4x^2+1+4x^2

\implies 6x^2+6x+1=1

Subtract 1 from both sides:

\implies 6x^2+6x+1-1=1-1

\implies 6x^2+6x=0

Factor out the common term 6x:

\implies 6x(x+1)=0

Apply the <u>zero-product property</u>:

\implies 6x=0 \implies x=0

\implies (x+1)=0 \implies x=-1

Substitute the found values of x into one of the equations and solve for y:

\textsf{When } \: x = 0\implies y=-4(0)^2+1=1

\textsf{When } \: x = -1\implies y=-4(-1)^2+1=-3

Therefore, the solutions to the given <u>system of equations</u> are (0, 1) and (-1, -3).

Learn more about systems of equations here:

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6 0
1 year ago
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