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3 years ago

How do you do 185 times 12 in standard algorithm?

Mathematics

1 answer:

jolli1 [7]3 years ago

6 0

the answer is 2,220

you first aline 185 × 12 like so 185

× 12

then you need to multiply everything

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Find the GCF

Kaylis [27]

Greatest Common Factor. let's go over that. GCF of 6 and 12 would be 6 because 6 goes into 6, 1 times and 6 goes into 12, 2 times. . and it is the largest. so first you see if the lower number can go directly into the higher number. So 28a^2 b^2 c^2, is made of 14abc× 2abc. so you can say 14abc goes into 28a2b2c2, 2abc times. therefore 14abc is the largest factor.

7 0

3 years ago

In the diagram below, ΔPQR ≅ ΔSTR. Complete the statement ∠PRQ ≅ ___ A. ∠SRT B. ∠RST C. ∠STR D. ∠T

Oduvanchick [21]

The complete statement is ∠PRQ ≅ <u>∠SRT</u>. The correction option is A. ∠SRT

<h3>Similar triangles </h3>

From the question, we are to complete the given statement

From the given information,

We have that ΔPQR ≅ ΔSTR

This means ΔPQR is congruent to ΔSTR

Then,

∠PQR ≅ ∠STR

∠PRQ ≅ ∠SRT

∠QPR ≅ ∠TSR

Hence, the complete statement is ∠PRQ ≅ <u>∠SRT</u>. The correction option is A. ∠SRT

Learn more on Congruent Triangles here: brainly.com/question/28032367

#SPJ1

4 0

2 years ago

Please answer at least one of them.

dsp73

Hey there find an image attached..

8 0

3 years ago

Read 2 more answers

An airplane pilot over the Pacific sights an atoll at an angle of depression of 5 . At this time, the horizontal distance from t

Aleonysh [2.5K]

Answer:

404.98 m

Step-by-step explanation:

The angle of depression is 5°

The horizontal distance from the airplane to the atoll is 4629 meters.

We need to find the height of the plane.

If we consider a triangle. 4629 meters will be the base and angle is 5°. Let h is the height of the plane. Using trigonometry to find it :

$\tan\theta=\dfrac{x}{4629 }\\\\\tan(5)=\dfrac{x}{4629 }\\\\x=\tan(5)\times 4629 \\\\x=404.98\ m$

So, the height of the plane is 404.98 m.

6 0

3 years ago

Consider the following hypothesis test:

Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

$H_0: \mu\leq50\\\\H_a:\mu> 50$

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809$

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24$

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

8 0

4 years ago