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marishachu [46]
3 years ago
12

The ratio of the perimeters of two similar triangles is 4:7. What is the area of each of these triangles if the sum of their are

as is 65cm^2.
Mathematics
1 answer:
garri49 [273]3 years ago
3 0
For similar triangles, it is just 4^2 and 7^2

So for the smaller triangle, the area is 16, and for the bigger one, it is 49
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Tyler goes to the store. His budget is $125. Which inequality represents x, the amount in dollars Tyler can spend at the store?
raketka [301]

Answer:

The answer is A

Step-by-step explanation:

If Tyler's budget is $125, he cannot spend more than that. He can spend at most $125; which is represented as less than or equal to.

x \leqslant 125

6 0
3 years ago
On a number line what is the distance between -3/2 and 6?
sesenic [268]

Answer:

  • 7.5 units

Step-by-step explanation:

The distance is always positive and is same as the absolute value of subtraction of the two numbers on the line.

<u>This can be shown as:</u>

  • |-3/2 - 6| =
  • |-1.5 - 6| =
  • |-7.5| =
  • 7.5

or

  • | 6 - (-3/2)| =
  • |6 + 1.5| =
  • |7.5| =
  • 7.5
6 0
2 years ago
Read 2 more answers
Pat ran 18/24 of the distance to the park what is the fraction in simplest form
Nikitich [7]
18/24 can both be divided by 6, so it's 3/4
3 0
3 years ago
Read 2 more answers
2. On Monday, I bought 3 dogs and 5 cats for a total cost of $8.25. On Tuesday, I bought 3 dogs and 6 cats for a total cost of $
Ratling [72]
I don’t know if you need to round, but you can do so on the answer for mondays if necessary

On Monday, the animals cost $1.03125.
On Tuesday, the animals cost exactly $1.
7 0
2 years ago
(secx)dy/dx=e^(y+sinx), please help me solve the differential equation. Thanks :)
nalin [4]
First, you must know these formula  d(e^f(x) = f'(x)e^x dx, e^a+b=e^a.e^b, and d(sinx) = cosxdx, secx = 1/ cosx

(secx)dy/dx=e^(y+sinx), implies  <span>dy/dx=cosx .e^(y+sinx), and then 
</span>dy=cosx .e^(y+sinx).dx, integdy=integ(cosx .e^(y+sinx).dx, equivalent of 
integdy=integ(cosx .e^y.e^sinx)dx, integdy=e^y.integ.(cosx e^sinx)dx, but we know that   d(e^sinx) =cosx e^sinx dx,
so integ.d(e^sinx) =integ.cosx e^sinx dx,
and e^sinx + C=integ.cosx e^sinxdx
 finally, integdy=e^y.integ.(cosx e^sinx)dx=e^2. (e^sinx) +C
the answer is 
y = e^2. (e^sinx) +C, you can check this answer to calculate dy/dx
7 0
3 years ago
Read 2 more answers
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