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marishachu [46]
3 years ago
12

The ratio of the perimeters of two similar triangles is 4:7. What is the area of each of these triangles if the sum of their are

as is 65cm^2.
Mathematics
1 answer:
garri49 [273]3 years ago
3 0
For similar triangles, it is just 4^2 and 7^2

So for the smaller triangle, the area is 16, and for the bigger one, it is 49
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Solve the triangle m<N= 118°, m<P= 33° and m=15. Round to the nearest tenth. Please show work.​
kirill [66]

Answer:

M = 29

27.31838095 = n

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Step-by-step explanation:

M = 180 -33-118 = 29

We can use the rule of sines

sin A          sin B           sin C

------------ = ---------- = ------------

a                  b               c

sin 118          sin 29        

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Using cross products

15 sin 118 = n sin 29

Divide by sin 29

15 sin 118 / sin 29 = n

27.31838095 = n

sin 33          sin 29        

------------ = ----------

p                  15              

Using cross products

15 sin 33 = p sin 29

Divide by sin 29

15 sin 33 / sin 29 = p

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3 0
2 years ago
You estimate that there are 45 marbles in a jar. The actual amount is 82 marbles. Find the percent error. Round to the nearest t
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Answer:

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cos^4(x)[sin(x)-1]=0\to 
\begin{cases}
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