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yKpoI14uk [10]
3 years ago
8

The sum of x and y decreased by their product

Mathematics
1 answer:
Ksju [112]3 years ago
8 0
(x+y) - xy is the answer
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Simplify (12a5−6a−10a3)−(10a−2a5−14a4) . Write the answer in standard form
almond37 [142]

Answer:

=14a^5+14a^4-10a^3-16a

Step-by-step explanation:

\left(12a^5-6a-10a^3\right)-\left(10a-2a^5-14a^4\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\=12a^5-6a-10a^3-\left(10a-2a^5-14a^4\right)\\-\left(10a-2a^5-14a^4\right):\quad -10a+2a^5+14a^4\\-\left(10a-2a^5-14a^4\right)\\\mathrm{Distribute\:parentheses}\\=-\left(10a\right)-\left(-2a^5\right)-\left(-14a^4\right)\\Apply\:minus-plus\:rules\\-\left(-a\right)=a,\:\:\:-\left(a\right)=-a\\=-10a+2a^5+14a^4\\=12a^5-6a-10a^3-10a+2a^5+14a^4

\mathrm{Simplify}\:12a^5-6a-10a^3-10a+2a^5+14a^4:\quad 14a^5+14a^4-10a^3-16a12a^5-6a-10a^3-10a+2a^5+14a^4\\Group\:like\:terms\\=12a^5+2a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:12a^5+2a^5=14a^5\\=14a^5+14a^4-10a^3-6a-10a\\\mathrm{Add\:similar\:elements:}\:-6a-10a=-16a\\=14a^5+14a^4-10a^3-16a

4 0
3 years ago
When a fraction of 17 is taken away from 17 what remains exceeds 1/3 of 17 by 6
MrRissso [65]
1/3×17/1=51/1

51+6=57
4 0
3 years ago
What is the volume of a sphere with radius of 16 inches?
matrenka [14]
Volume =
\frac{4}{3} \pi {r}^{3}  \\  =  \frac{4}{3}  \times 3.14 \times  {16}^{3}  \\  = 17148.59 \  {in}^{3}

The answer is the first option.

Hope this helps. - M
8 0
3 years ago
Read 2 more answers
A change purse contains an equal number of pennies, nickels, and dimes. The total value of the coins is 208
Aliun [14]

Answer:

x= 14

Step-by-step explanation:

x + 5x +10x = 224 CENTS

solving for x

16x = 224

x = 14, the number of each coin there is

5 0
3 years ago
Solve for c.<br><br> 5c+16.5=13.5+10c
Kruka [31]

Answer:

c = 3/5

Step-by-step explanation:

5c+16.5=13.5+10c

Subtract 5c from each side

5c-5c+16.5=13.5+10c-5c

16.5 = 13.5 +5c

Subtract 13.5 from each side

16.5 -13.5 =13.5-13.5 +5c

3 = 5c

Divide by 5

3/5 = 5c/5

3/5 =c

4 0
3 years ago
Read 2 more answers
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