Question

Square A has a side length (2x-7) and Square B has side length (-4x+18). How much bigger is the perimeter of Square B than Square A?

Answer 1

Answer:

The perimeter of Square B is (-24x+100) units much bigger than Square A.

Step-by-step explanation:

Side length of square A = (2x-7)

Side length of square B = (-4x+18)

Perimeter of a square is

$Perimeter=4a$

where, a is side length of square.

Perimeter of square A is

$Perimeter=4(2x-7)=4(2x)+4(-7)=8x-28$

Perimeter of square B is

$Perimeter=4(-4x+18)=4(-4x)+4(18)=-16x+72$

Difference between perimeter of Square B than Square A is

$Difference=-16x+72-(8x-28)$

$Difference=-16x+72-8x+28$

Combined like terms.

$Difference=(-16x-8x)+(72+28)$

$Difference=-24x+100$

Therefore, the perimeter of Square B is (-24x+100) units much bigger than Square A.

Answer 2

How much bigger is B than A , so Side length B- A = (-4x+18) - (2x-7) = -6x+25
So perimeter = 4x length = 4x(-6x+25) = -24x+100 = 100-24x 
How much bigger? 100-24X 

__Brainliest if i helped!