Givens
Petri Dish A sees a double ever 10 minutes
Petri Dish B sees a double ever 6 minutes
Consequences
A doubles 60 / 10 = 6 times.
B doubles 60 / 6 = 10 times.
Solution
If you work best with numbers then suppose there are 100 bacteria in both dishes at the beginning
A = 100 * 2^6
B = 100 * 2^10
A will have 100 * 64 = 6400 bacteria growing inside A
B will have 100 * 1024 = 102400 bacteria growing inside B
B/A = 102400 / 6400 = 16
There are 16 times as many in B than in A. <<<< Answer
Answer:
does it have a picture
Step-by-step explanation:
71/20 is not in simplest form because you need to change it into a mixed number by dividing 71 and 20 and putting the remainder over 20.
OK im answering ............................................................................................................
Answer:
option K cuz
Step-by-step explanation:
if we take m=7 and n=2
7 + 2= 9
and 9 is an odd number
