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4 years ago

A piece of wood used for construction is 2 inches by 4 inches by 24 inches . What is the surface area of the wood ?

Mathematics

2 answers:

Kazeer [188]4 years ago

8 0

2•{(2•4)+(2•24)+(4•24)}= 304

Marina CMI [18]4 years ago

4 0

This is a 2 part problem. First, we need to find the area of each side, then add them together. (the question isn't asking for volume).

1) The board has six sides(top, bottom, four sides). the top + bottom are 4 by 24 in, the short sides are 2 by 4 inches, and the long sides are 2 by 24 inches. After multiplying, this gives us 96 sq in + 96 sq in for the top and bottom, 8 sq in and 8 sq in for the short sides, and 48 sq in + 48 sq in for the long sides.

2) If we add all of these together, we get 96 + 96 + 8 + 8 + 48 + 48 = 192 + 16 + 96 = 304 sq inches, which is the total surface area.

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3 years ago

What's the largest 3-digit base 14 integer?

Mars2501 [29]

Base 10 has the ten digits: {0, 1, 2, 3, 4, 5, 6,7, 8, 9}

Base 11 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A} where A is treated as a single digit number

Base 12 has the digits {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B}

Base 13 has the digits: {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C}

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Note: It is similar to how 999 is the largest 3-digit base 10 integer

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3 years ago

Which of the following graphs represents the function f(x) = x2 + x − 6?

Darya [45]

The answer is: D

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Focus: (−1/2, −6)

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3 years ago

Read 2 more answers

16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.

Katyanochek1 [597]

We will use the sine and cosine of the sum of two angles, the sine and consine of $\frac{\pi}{2}$ , and the relation of the tangent with the sine and cosine:

$\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta$

$\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0$

$\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}$

If you use those identities, for $\alpha=x,\ \beta=\dfrac{\pi}{2}$ , you get:

$\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x$

$\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x$

Hence:

$\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x$

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4 years ago