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3 years ago

A piece of wood used for construction is 2 inches by 4 inches by 24 inches . What is the surface area of the wood ?

Mathematics

2 answers:

Kazeer [188]3 years ago

8 0

2•{(2•4)+(2•24)+(4•24)}= 304

Marina CMI [18]3 years ago

4 0

This is a 2 part problem. First, we need to find the area of each side, then add them together. (the question isn't asking for volume).

1) The board has six sides(top, bottom, four sides). the top + bottom are 4 by 24 in, the short sides are 2 by 4 inches, and the long sides are 2 by 24 inches. After multiplying, this gives us 96 sq in + 96 sq in for the top and bottom, 8 sq in and 8 sq in for the short sides, and 48 sq in + 48 sq in for the long sides.

2) If we add all of these together, we get 96 + 96 + 8 + 8 + 48 + 48 = 192 + 16 + 96 = 304 sq inches, which is the total surface area.

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Answer:

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Step-by-step explanation:

Given

$s = 10|x - 4| + 50$

Required

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Subtract 50 from both sides

$80 - 50= 10|x - 4| + 50 - 50$

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Reorder

$|x - 4| = 3$

This can be split into

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Hence:

<em>The numbers of measure of music played are 1 and 7</em>

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3 years ago

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inn [45]

Answer:

Follows are the solution to the given point:

Step-by-step explanation:

For option A:

In the first point let z be the number of heads which is available on the first two trails of tosses so, the equation is:

$P(X=k | z=2 ) = \begin{pmatrix} 10-2\\ k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k}$

$= \begin{pmatrix} 8\\k-2\end{pmatrix} (\frac{1}{2})^{k-2} (\frac{1}{2})^{10-k} \ \ \ \ \ \ \ \ \ \ \\\\$

$k= 2,3..........10$ For option B:

$P(X=k | X \geq 2 ) = \sum^{10}_{i=2} \begin{pmatrix} 10-i\\ k-i\end{pmatrix} (\frac{1}{2})^{k-i} (\frac{1}{2})^{10-k}$

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3 years ago

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Katyanochek1 [597]

Ok the ladder and the ground will make a right triangle/right angle. This is because the ground is flat, the wall is straight and only the ladder is leaning/slanted. I hope this helps.

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Elodia [21]

Answer:

Step-by-step explanation:

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Vilka [71]

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