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kenny6666 [7]
3 years ago
10

PLEASE HELP! WILL MARK THE FIRST CORRECT ANSWER BRAINLIEST!

Mathematics
2 answers:
jek_recluse [69]3 years ago
8 0

Answer:

$18

Step-by-step explanation:

(amount of candy1)(cost of candy1) + (amount of candy2)(cost of candy2) = total cost of mixture

6 lb * $2 + 4 lb * $1.50 = x

12 + 6 = x

x = $18

The price of the mixture is $18.

crimeas [40]3 years ago
4 0

Answer:

18 dollars

Step-by-step explanation:

x=6*2+4*1.5

x=12+6

x=18

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Ryan bought 3 books and a magazine . He paid $30 and relieved $5 change if the magazine cost twice as much as each book, find th
Montano1993 [528]

The books are $5, and the magazines are $10. I’m not sure which way you want it explained but since magazines are twice the price of books, you can solve the equation 3b + 2b = 25. This gives you b=5 which you just multiply by 2 giving you the price of a magazine.

8 0
3 years ago
Read 2 more answers
What is the volume of this prism?
Mandarinka [93]

Answer:

144 cm^3

Step-by-step explanation:

The formula for the volume of a rectangular prism is <em>l x w x h. </em>

Here, the length is 4, the width is 4, and the height is 4.

4 x 4 x 9 =

16 x 9 =

144 cm^3

8 0
3 years ago
In the parallelogram DEFG, DH=x+1, HF=3y, GH=3x-4, and HE=5y+1. Find the values of x and y. The diagram is not drawn to scale.
RideAnS [48]

Answer:

Step-by-step explanation:

Given:  In parallelogram DEFG,

DH = x + 1

HF = 3y

GH = 3x - 4

and HE = 5y + 1

Solution: Since, DH,HF, GH and HE represents the diagonals of the parallelogram and we know that the diagonals of the parallelogram bisect each other, therefore

x+1=3y            (1)

3x-4=5y+1      (2)

Multiply equation (1) with 3 and then subtract equation (2) from it, we get

3x+3-3x+4=9y-5y-1

7=4y-1

y=2

Substituting the value of y=2 in equation (1), we get

x+1=3(2)

x=5

Therefore, the value of x and y are 5 and 2 respectively.

8 0
3 years ago
Billy says that he can add 23 and 40 without regrouping is Bill correct how do you know
bija089 [108]
Yes he is correct because if you do the algorithm, 0+3=3 and 20+40=60 and 60+3=63. There is no regrouping needed.
6 0
3 years ago
Given f(x)= 2x²+4x-6 and g(x)=2x-2, find each function
valkas [14]
F(x)= 2x²+4x-6 and g(x)=2x-2, find each function
1. (f/g) (x) = f(x)÷g(x) = (2x²+4x-6)÷(2x-2)
First factor both top and bottom:
(2x-2)(x+3)÷(2x-2) = x+3

2. f(a + 2) = plug (a+2) in anywhere there is an x in f(x)=2x²+4x-6 -->
2(a+2)^2 +4(a+2)-6 = 2(a^2+4a+4)+4a+8-6, now distribute:
2a^2+8a+8+4a+2, combine like terms
2a^2+12a+10

3. g(a/2) = plug (a/2) in anywhere there's an x in g(x)=2x-2:
2(a/2)-2 = a-2
5 0
3 years ago
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