Question

The figures are similar. Give the ratio of the perimeters and the ratio of the areas of the first figure to the second.

Answer 1

Answer: first option.

Step-by-step explanation:

The ratio of the area of the triangles can be calculated as following:

$ratio_{(area)}=(\frac{l_1}{l_2})^2$

Where $l_1$ is the lenght of the given side of the smaller triangle and $l_2$ is the lenght of the given side of the larger triangle.

Therefore:

$ratio_{(area)}=(\frac{28}{32})^2=\frac{49}{64}$

It can be written as following:

$ratio_{(area)}=49:64$

The ratio of the perimeter is:

$ratio_{(perimeter)}=\frac{l_1}{l_2}$

Where $l_1$ is the lenght of the given side of the smaller triangle and $l_2$ is the lenght of the given side of the larger triangle.

Therefore:

$ratio_{(perimeter)}=\frac{28}{32}=\frac{7}{8}$

It can be written as following:

$ratio_{(perimeter)}=7:8$