Refer to the figure below to complete the following item.

Mathematics

2 answers:

Dmitrij [34]3 years ago

5 0

Answer:

160

Step-by-step explanation:

Dmitriy789 [7]3 years ago

5 0

Answer:

100

Step-by-step explanation:

if they are on the same line the angles are the same. Just took this and

what the answer was

You might be interested in

Alaina has 7 in her bank account and earns 6 each day . joel has 48 in his banck account and earn 8 earch day in how many days w

Elis [28]

Answer:

I think you wrote something wrong.

Step-by-step explanation:

If Alaina has $7 in her bank account and Joel had $48 in his Joel already has more then Alaina but I will attempt to teach you how to solve these types of problems.

for this example I'm giving Alaina 79 dollars.

First we know were starting with 79 dollars and increasing 6 dollars each day so the equation for this is; y = 6x + 79 that is Alaina's equation.

For Joel our equation will be; y = 8x + 48.

Since they already have 79 and 48 dollars in their bank we put those as our B in the equation cause they are our y-intercepts. (Y = mx + b) Next we know their increasing by 6 and 8 dollars a day so we make those our m. Once we have these equations we can plot them and see where the lines meet. (thats our answer) I plotted them on desmos graphing calculator.

They crossed at (15.5, 172) Which means it will take 16 days for Joel to catch up they will both have 172 dollars in the bank account on the 16th day.

Hope this helps!

8 0

2 years ago

PLEASE HELP

lozanna [386]

It’s 46 hope that helps I don’t know how to put a picture of the work I did on here but I ta 46

4 0

3 years ago

Solve the equation in the complex number system. x^2-12x+40=0

mylen [45]

solving the equation $x^2-12x+40=0$ we get $x=6+2i\,\,and\,\,x=6-2i$

Step-by-step explanation:

Solve the equation:

$x^2-12x+40=0$

We can solve using quadratic Formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a= 1, b = -12, c = 40

Putting values:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-12)\pm\sqrt{(-12)^2-4(1)(40)}}{2(1)}\\x=\frac{12\pm\sqrt{144-160}}{2}\\x=\frac{12\pm\sqrt{-16}}{2}\\We\,\,know\,\,\sqrt{-1}=i\\ x=\frac{12\pm4i}{2}\\ x=\frac{12+4i}{2}\,\,and\,\, x=\frac{12-4i}{2}\\ x=\frac{4(3+i)}{2}\,\,and\,\, x=\frac{4(3-i)}{2}\\x=2(3+i)\,\,and\,\,x=2(3-i)\\x=6+2i\,\,and\,\,x=6-2i$