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White raven [17]
3 years ago
6

What is the volume of one cylinder?

Mathematics
2 answers:
Rufina [12.5K]3 years ago
7 0

Answer:

See picture:)

Hope that makes sense! If you'd like any more help with maths, I'd be happy to offer online tuition. You can find me at: www.birchwoodtutors.com

suter [353]3 years ago
3 0
If you need the radius or height I will send another picture

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What is equivalent to 7^13/7^7
Deffense [45]

The equivalent expression to 7^13/7^7 would be 7^6.

<h3>What are equivalent expressions?</h3>

Those expressions that might look different but their simplified forms are the same expressions are called equivalent expressions.

To derive equivalent expressions of some expression, we can either make it look more complex or simple. Usually, we simplify it.

We have given an expression as  7^13/7^7

The equivalent expression;

\dfrac{7^{13}}{7^7} \\\\7^{13-7}\\\\7^6

Hence, The equivalent expression to 7^13/7^7 would be 7^6.

Learn more about expression;

brainly.com/question/22246485

#SPJ1

3 0
2 years ago
Sphere with a radius of a radius of 42 inches
prisoha [69]

Answer:

310339.1 in^3

Step-by-step explanation:

Volume=4/3*pi*r^3

Volume=4/3*pi*42^3

Volume=4/3*pi*74088

Volume=98784*pi

Volume=310339.0887

So the volume is about 310339.1 in^3

5 0
3 years ago
A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee
katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

^nC_r=\dfrac{n!}{(n-r)!r!}

Given : Total multiple-choice questions  = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= ^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84

No. of ways to answer 4 open-ended problems

= ^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= 84\times15=1260

Hence, the correct answer is option A) 1260

5 0
3 years ago
PLEASE HELP ME<br> MATH IS HARD
nata0808 [166]

Answer:

C

Step-by-step explanation:

You have to add the whole equation not only a part of it.

3 0
3 years ago
Read 2 more answers
Is the answer C ; y= -3x-1
Sonja [21]

Answer:

I believe you are correct

Hope This Helps!      Have A Nice Day!!

8 0
4 years ago
Read 2 more answers
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