well, Diego is 4 now, so by his 18th birthday that'll be 14 years later.
![~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$1600\\ r=rate\to 8.25\%\to \frac{8.25}{100}\dotfill &0.0825\\ t=years\dotfill &14 \end{cases} \\\\\\ A=1600[1+(0.0825)(14)]\implies A=1600(2.155)\implies A=3448](https://tex.z-dn.net/?f=~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%241600%5C%5C%20r%3Drate%5Cto%208.25%5C%25%5Cto%20%5Cfrac%7B8.25%7D%7B100%7D%5Cdotfill%20%260.0825%5C%5C%20t%3Dyears%5Cdotfill%20%2614%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D1600%5B1%2B%280.0825%29%2814%29%5D%5Cimplies%20A%3D1600%282.155%29%5Cimplies%20A%3D3448)
Answer:
sec(theta°)cos(theta°) = 1
Step-by-step explanation:
given data
(theta°) = 225
to find out
sec(theta°)cos(theta°)
solution
as we know that given equation
(theta°) = 225
cos(theta°) will be
cos(225°) = -0.7071 .................................1
so we know
sec(theta°) =
..............2
so put here value of cos(theta°)
sec(theta°) =
sec(theta°) = - 1.4142
so
sec(theta°)cos(theta°) = -0.7071 × ( - 1.4142 )
sec(theta°)cos(theta°) = 1
so answer is sec(theta°)cos(theta°) = 1
Answer:
-4d
Step-by-step explanation:
L.c.m=15
15×2/5(d-10)-2/3×15(d+6)
3×2(d-10)-2×5(d+6)
6(d-10)-10(d+6)
6d-60-10d-60
6d-10d-60-60
-4d-0
-4d
<span>37.7
The formula is </span>V=<span><span>π<span>r^2*</span></span><span>h/3, and since r is 4/2, you multiply it by </span></span><span><span>π and then multiply it h/3, which is 9/3, so ((2*3.14)*3)= 37.7.</span></span>
The answer to "Round 10.054 To 2 decimal places" is 10.05