4 years ago

Rx+9/5=h, Solve for the value of x

Mathematics

1 answer:

muminat4 years ago

5 0

rx+(9/5)=h

rx=h-(9/5)

x=(h-(9/5))/r

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Just 24 plz, I am struggling

Bingel [31]

check the pictured below.

now, notice that APB is just a flat-line and therefore those two angles there add up to 180°.

also notice that since ∡ACB is 90°, then those two angles add up to that much.

$\bf \stackrel{\measuredangle ACP}{(3x+2y)}+\stackrel{\measuredangle BCP}{(3x+4y)}=90\implies 6x+6y=90\implies \stackrel{\textit{common factor}}{6(x+y)}=90
\\\\\\
x+y=\cfrac{90}{6}\implies x+y=15\implies \boxed{x=15-y}
\\\\[-0.35em]
~\dotfill$

$\bf \stackrel{\measuredangle APC}{(7x+3)}+\stackrel{\measuredangle BPC}{(16y)}=180\implies 7x+16y=177\implies 7\left( \boxed{15-y} \right)+16y=177
\\\\\\
105-7y+16y=177\implies 9y=72\implies y=\cfrac{72}{9}\implies \blacktriangleright y=8 \blacktriangleleft
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\measuredangle BPC=16(8)\implies \measuredangle BPC=128$