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3 years ago

Hope an expert can help with this

Mathematics

1 answer:

worty [1.4K]3 years ago

7 0

if there are 300 raffle tickets and one raffle ticket is drawn, the proabability of drawing the next one is 1 in 299 because there is one less ticket from the previous win

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What are the solutions of the system 7x + 3y=-3 and y= -2*?

mafiozo [28]

Answer:

opt 4

Step-by-step explanation:

when x=0, 0+3y= -3, so y=-1 (0,-1) is solution

when x=3 , 21+3y=-3, 3y= -3-21= -24

y= -8 (3,-8) is also solution

8 0

3 years ago

A scientist has 100 milligrams of a radioactive element. The amount of radioactive element remaining after t days can be determi

grandymaker [24]

The mass of the first shipment at time t is
$m_{1}=100( \frac{1}{2} )^{ \frac{t}{10}}$

The mass of the second shipment at time t is
$m_{2}=100( \frac{1}{2} )^{ \frac{t-3}{10} }$

At time t, the ratio of m₁ to m₂ is
$\frac{m_{1}}{m_{2}} = \frac{100}{100}. \frac{(1/2)^{t/10}}{(1/2)^{(t-3)/10}} \\ = \frac{(1/2)^{t/10}}{(1/2)^{t/10}}. \frac{1}{(1/2)^{-3/10}} \\ = (1/2)^{3/10} \\ = 0.8123$

Therefore as a percentage,
$\frac{m_{1}}{m_{2}} =100*0.8123 = 81.23 \%$

Answer: B. 81.2%

4 0

3 years ago

Milo drives 126 miles on 7.5 gallons of gas. How far does he travel on each gallon of gas? 1.68 miles 16.8 miles 168 miles 1,680

Tanzania [10]

The answer is B. 16.8

8 0

3 years ago

Read 2 more answers

Find a number that is between 8/11 and 0.85(repeating) .

professor190 [17]

The answer is C. If you have any questions then leave a comment. Good luck!

7 0

3 years ago

A survey of 46 college athletes found that 24 played volleyball, while 22 played basketball. a) If we pick one athlete survey pa

PSYCHO15rus [73]

Answer:

A) $\dfrac{11}{23}$

B) $\dfrac{88}{345}$

Step-by-step explanation:

A survey of 46 college athletes found that

24 played volleyball,
22 played basketball.

A) If we pick one athlete survey participant at random, the probability they play basketball is

$P_1=\dfrac{22}{46}=\dfrac{11}{23}$

B) If we pick 2 athletes at random (without replacement),

the probability we get one volleyball player is $\dfrac{24}{46}=\dfrac{12}{23};$
the probability we get another basketball player is $\dfrac{22}{45}$ (only 45 athletes left).

Thus, the probability we get one volleyball player and one basketball player is

$P_2=\dfrac{12}{23}\cdot \dfrac{22}{45}=\dfrac{88}{345}$

5 0

3 years ago