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masya89 [10]
3 years ago
12

Solve for w. = w-2/3=18 - 3w+18/2 Simplify your answer as much as possible.

Mathematics
1 answer:
mart [117]3 years ago
8 0
I have a screenshot of the answer

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9sin(2x) sin (x) = 9cos(x)
nikdorinn [45]

Answer:

\sin(2x)  = 2 \sin(x)  \cos(x)  \\ 9( 2 \sin(x)  \cos(x) ) \sin(x)  = 9 \cos(x)  \\ 18 { \sin}^{2} (x)9 \cos(x)  - 9 \cos(x)  = 0 \\ 9 \cos(x) (2{ \sin}^{2} (x) - 1) = 0 \\ 9 \cos(x) = 0 \: or \: 2{ \sin}^{2} (x) - 1 = 0 \\  \sin(x)  =  \pm \frac{1}{ \sqrt{2} }  \\  \cos(x)  = 0 \\ x =  { \cos}^{ - 1} (0) \\ x =  \frac{ \pi}{2}  = 90 \degree \\ x = \frac{ \pi}{2} + 2\pi \: n \:  \forall \: n \:  \in \:  \Z  \\ = 90 \degree +  360\degree\: n \:  \forall \: n \:  \in \:  \Z \\  =  \pm\frac{ \pi}{4}  \pm2\pi \: n \:  \forall \: n \:  \in \:  \Z \\ x =  \pm45\degree  \pm 360\degree\: n \:  \forall \: n \:  \in \:  \Z

8 0
2 years ago
The price of rail tickets increased by 5%
Arte-miy333 [17]
5% = 2.30pounds
2.30 ÷  0.05 = 46 pounds 
7 0
3 years ago
The point A (5,11) is reflected across the x-axis. How long is the segment AA'?<br>​
Nikitich [7]

Answer:  The required length of the segment AA' is 11 units.

Step-by-step explanation:  Given that the point A(5, 11) is reflected across the X-axis.

We are to find the length of the segment AA'.

We know that

if a point (x, y) is reflected across X-axis, then its co-ordinates becomes (x, -y).

So, after reflection, the co-ordinates of the point A(5, 11) becomes A'(5, -11).

Now, we have the following distance formula :

The DISTANCE between two points P(a, b) and Q(c, d) gives the length of the segment PQ as follows :

PQ=\sqrt{(c-a)^2+(d-b)^2}.

Therefore, the length of the segment AA' is given by

AA'=\sqrt{(5-5)^2+(-11-11)^2}=\sqrt{11^2}=11.

Thus, the required length of the segment AA' is 11 units.

7 0
3 years ago
Solve for N <br><br> (x^3)^3 = x^n
3241004551 [841]

Answer:

9

Step-by-step explanation:

( { {x}^{3}) }^{3}  =  {x}^{3 \times 3}thus n=3×3

which is equal to 9

4 0
3 years ago
URGENT
ch4aika [34]

slope =  \frac{y1 - y2}{x1 - x2}

slope =  \frac{ya - yb}{xa - xb}  \\  \\ slope =  \frac{18 - 2}{ - 3 - 5}  =  \frac{16}{ - 8} =  - 2

So B is the correct answer

7 0
3 years ago
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