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wolverine [178]
3 years ago
10

Function is defined by f(x) = x2 - 4x + 8. The graph of function g is shown.

Mathematics
1 answer:
xenn [34]3 years ago
3 0

Answer:5

Step-by-step explanation:

couldn’t tell ya g

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The area of a circular swimming pool is approximately 18m What is the radius​
olga nikolaevna [1]

Answer:

r≈2.39

Step-by-step explanation:

7 0
3 years ago
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A woman has a total of $9,000 to invest. She invests part of the money in an account that pays 7 % per year and
Volgvan

Answer:

Hi! I believe this is your answer:

$750

Step by step explanation:

interest + interest      = total interest

0.08*x   + 0.09*(9000-x) = 750    dollars

0.08x + 810 - 0.09x = 750

-0.01x = 750 - 810 = -60  ====>  x = %28-60%29%2F%28-0.01%29 = 6000.

Final answer:  

$6000 was invested at 8%.  The rest   9000-6000 = 3000 dollars were invested at 9%.

Check.   0.08*6000 + 0.09*3000 = 480 + 270 = 750 dollars.

6 0
2 years ago
What is the definition of exponential decay?
Lina20 [59]
When a population or group of something is declining, and the amount that decreases is proportional to the size of the population.
Have a good day!!
6 0
3 years ago
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On a coordinate plane, a circle has a center at point (negative 6, 4). What is the equation of the circle shown in the graph? (
lukranit [14]

Answer:

1) x+6 2)y-4 3)36

Step-by-step explanation:

(x+6)² + (y-4)² = 36

5 0
3 years ago
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The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
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