Answer : The boiling point of the resulting solution is, ![100.6^oC](https://tex.z-dn.net/?f=100.6%5EoC)
Explanation :
Formula used for Elevation in boiling point :
![\Delta T_b=i\times k_b\times m](https://tex.z-dn.net/?f=%5CDelta%20T_b%3Di%5Ctimes%20k_b%5Ctimes%20m)
or,
![T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}](https://tex.z-dn.net/?f=T_b-T%5Eo_b%3Di%5Ctimes%20k_b%5Ctimes%20%5Cfrac%7Bw_2%5Ctimes%201000%7D%7BM_2%5Ctimes%20w_1%7D)
where,
= boiling point of solution = ?
= boiling point of water = ![100^oC](https://tex.z-dn.net/?f=100%5EoC)
= boiling point constant = ![0.52^oC/m](https://tex.z-dn.net/?f=0.52%5EoC%2Fm)
m = molality
i = Van't Hoff factor = 1 (for non-electrolyte)
= mass of solute (sucrose) = 5.0 g
= mass of solvent (water) = 10.0 g
= molar mass of solute (sucrose) = 342.3 g/mol
Now put all the given values in the above formula, we get:
![(T_b-100)^oC=1\times (0.52^oC/m)\times \frac{(5.0g)\times 1000}{342.3\times (10.0g)}](https://tex.z-dn.net/?f=%28T_b-100%29%5EoC%3D1%5Ctimes%20%280.52%5EoC%2Fm%29%5Ctimes%20%5Cfrac%7B%285.0g%29%5Ctimes%201000%7D%7B342.3%5Ctimes%20%2810.0g%29%7D)
![T_b=100.6^oC](https://tex.z-dn.net/?f=T_b%3D100.6%5EoC)
Therefore, the boiling point of the resulting solution is, ![100.6^oC](https://tex.z-dn.net/?f=100.6%5EoC)
For the temperature to go down, the average kinetic energy must decrease which means that the kinetic energy of the gas molecules must decrease. Since energy is neither created nor destroyed, and energy is not "lost" due to gas molecule collisions (they are elastic), then the KE must be transferred to the molecules of some other substance at a lower temperature.
Bellow you my find the chemical equations of the ionization of a triprotic acid.
Explanation:
The chemical equations for the ionization of phosphoric acid (H₃PO₄), which is a triprotic acid, in water:
H₃PO₄ (s) + H₂O (l) → H₂PO₄⁻ (aq) + H₃O⁺ (aq)
H₂PO₄⁻ (aq) + H₂O (l) → HPO₄²⁻ (aq) + H₃O⁺ (aq)
HPO₄²⁻ (aq) + H₂O (l) → PO₄³⁻ (aq) + H₃O⁺ (aq)
where:
(s) - solid
(l) - liquid
(aq) - aqueous
Learn more about:
triprotic acid
brainly.com/question/9974667
#learnwithBrainly
The volume of the gas V2 is 66.67 L
<u>Explanation:</u>
<u>Given data</u>
V1= 59.5 L
V2=?
T1= 121K Pa
T2= 108 K Pa
We have the formula,
V1/T1 =V2/T2
Rewrite the formula as,
V2= VI T1/T2
V2= 59.5 L * 121 K Pa/108 K Pa
V2=7199.5 L K Pa/ 108 K Pa
V2=66.67 L
The volume of the gas V2 is 66.67 L