Which chemical reaction involves the fewest oxygen atoms?

Chemistry

1 answer:

ohaa [14]3 years ago

7 0

Answer:

4Fe + 6H2O + 3O2 -------> 4Fe(OH)3

Explanation:

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if you have five grams of product after a chemical reaction,how many grams of ractants did you have at the start of the reaction

Kitty [74]

Due to the law of conservation of mass, you will end up with the same as what you started with. So in this case, five grams.
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3 years ago

Explain how both analytical and creative problem-solving strategies can be applied to the following scenario. Jeff notices that

Over [174]

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3 years ago

Which element will never react, neon (Ne) or hydrogen (H)?

Zarrin [17]

Answer:

Neon(Ne)

Explanation:

Neon will not react because it is a noble gas and had 8 electrons.

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3 years ago

Read 2 more answers

What type(s) of intermolecular forces are expected between PF2Cl3 molecules?a. dispersion.b. dipole-dipole.c. ion-ion.d. hydroge

m_a_m_a [10]

Answer:

dispersion.

Explanation:

The molecule, PF2Cl3 is trigonal bipyramidal. The dipoles in the molecule cancel out since there is a symmetric charge distribution around the molecule hence the resultant dipole moment of the molecule is zero.

If the molecule is nonpolar, then the dominant intermolecular forces present are the weak dispersion forces, hence the answer above.

3 0

3 years ago

How many grams and what is the limiting reactent?

gayaneshka [121]

Hello!

1) What is the limiting reactant?

The chemical equation for this reaction is:

2Al(OH)₃ → Al₂O₃ + 3H₂O

The Limiting Reactant is the one that is in the lowest amount in the reaction and determines how many moles are produced. You can see that in this chemical equation there is only one reactant since this reaction is a decomposition reaction. So, the limiting reactant is Al(OH)₃.

2) How many grams of water are produced?

The chemical equation for this reaction is:

2Al(OH)₃ → Al₂O₃ + 3H₂O

So, we are going to use the following conversion factor to go from grams of Al(OH)₃ to grams of water:

$17,8 g Al(OH)_3* \frac{1 mol Al(OH)_3}{78 g Al(OH)_3}* \frac{3 moles H_2O}{2 moles Al(OH)_3}* \frac{18,015 g H_2O}{1 mol H_2O} \\ =6,17 g H_2O$

So, 6,17 grams of Water are produced.

Have a nice day!

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4 years ago