The answer is 6 because you do 6-2 the add 2
There is so much controversy about this question on the internet (well not this question exactly but the idea of taking a reciprocal of a discontinuous function).
Some say you can if you make it clear that the point causing the trouble is excluded in some way. Others say that you cannot contemplate the idea. You are creating a meaningless situation with no definition. It really depends on what you have been told about division by 0. There are ways of getting around this, but you are not taking a calculus course and therefore you likely don't have the tools to deal with it. In any event, it does not look to me like you know about limits yet.
Your marker or teacher or tutor can go either way on this problem and be justified in marking you wrong no matter what you do. As instructed I will put what I think should be done in the comment section. And remember, I'm counting noses and going with the majority when I answer this. It's not anything I'm 100% certain of, but neither is anyone else.
Answer: Picking the letter A.
Step-by-step explanation: I looked up what as likely as not meant and it means very probable so there's a probable chance of picking the letter A.
Answer:
The answer would be A. 1 1/5
48/40 = 1 8/40
1 8/40 Simplify to 1 1/5
V=4/3pi(r^3)
V=4/3pi(9^3)
V=3,054 inches^3
Hope this helps!!!!!!!!!
Step-by-step explanation:
from the graph attached below:
domain of graph is the value of x for which the given function profit function p(x) is defined.
(a) the domain represents the number of years for which the outlet will earn a profit.
range of profit function defines the lowest to highest value of profit earned.
(b) the range of this function is (0 , 160 ). for this function, the range represents the outlet's profit earned.
Answer:
a. 1965
b. 8 years
Step-by-step explanation:
For answers to questions like these it can work to consider the smallest possible dataset.
<h3>Dataset</h3>
For our purpose, consider the 9 years/values to be averaged to be ...
1, 2, 3, 4, 5, 6, 7, 8 ,9
<h3>Observations</h3>
a. The center value of the data set is 5. Its number is 5-1=4 more than the first one.
The first centered value is from the year 1961 +4 = 1965.
b. The 4 values at the beginning, and the 4 values at the end do not have a corresponding "average" value. That is, 4+4 = 8 values in the series are lost with respect to the number of average values.
8 years of values are lost.
