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Paha777 [63]
3 years ago
9

Hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhtdgdmdddddddd

Mathematics
2 answers:
jekas [21]3 years ago
6 0
Djjaiahsnajajsjsjjsjsjshsjsjs
disa [49]3 years ago
5 0

Answer:

I'm pretty sure its hgggahajajjejsjksksksksk

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Find the area of the equilateral triangle whose sides are 4 yd.
suter [353]

Answer:

The first one. 4 times square root of 3.

Step-by-step explanation:

The side of the equilateral triangle that represents the height of the triangle will have a length of because it will be opposite the 60o angle. To calculate the area of the triangle, multiply the base (one side of the equilateral triangle) and the height (the perpendicular bisector) and divide by two.

4 0
3 years ago
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HELP PLS WILL GIVE A LOT OF POINT
sveta [45]

Answer:

large = 18 3/4 = 18.75

small = 13/2 = 6 1/2 = 6.5

Step-by-step explanation:

Let l = the weight of large boxes

s = weight of small boxes

2 large and 3 small weights 57

2l+3s = 57

6 large and 5 small wights 145

6l+5s = 145

Multiply the first equation by 3

3(2l+3s) = 57*3

6l +9s =171

Subtract the second equation

6l +9s =171

-6l -5s = -145

-----------------------

     4s =26

Divide each side by 4

4s/4 = 26/4

s = 26/4 = 13/2

Substitute this into the first equation

2l +3s = 57

2l + 3(13/2) =57

Multiply by 2 to get rid of the fractions

2(2l + 3(13/2)) =57*2

4l + 39 = 114

Subtract 39 from each side

4l +39-39 = 114-39

4l =75

Divide by 4

4l/4 = 75/4

l = 75/4 = 18 3/4

7 0
3 years ago
Read 2 more answers
Triangle ABC is transformed to obtain triangle A′B′C′:
GaryK [48]

Answer:

327

Step-by-step explanation:

7 0
3 years ago
On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
Elena L [17]

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

7 0
3 years ago
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Will mark YOU brainliest!!
Akimi4 [234]

Answer: 15 miles per gallon

Step-by-step explanation:

135 divided by 9

5 0
2 years ago
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