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Paha777 [63]
3 years ago
9

Hhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhtdgdmdddddddd

Mathematics
2 answers:
jekas [21]3 years ago
6 0
Djjaiahsnajajsjsjjsjsjshsjsjs
disa [49]3 years ago
5 0

Answer:

I'm pretty sure its hgggahajajjejsjksksksksk

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What is the index of ⁴√81<br>​
ludmilkaskok [199]

Answer:

8

HOPING MAKATULONG PO!,KEEP SMILLING GOD LOVES YOU:)!

3 0
2 years ago
Questions is in the picture. no links please illl give brainly and 50 points only if answered properly
ohaa [14]

Answer:

subtract

a) 13/20

b) 1/2

c) 5/24

d) 7/18

e) 7/20

f) 3/40

Add or subtract

a) 4/9

b) 1/2

c) 11/20

d) 1/4

e) 19/12 <u>or </u>1 \frac{7}{12}

f) 4/21

3 0
3 years ago
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It is Converse, contrapositive and Inverse
Klio2033 [76]

Answer:

if you eat broccoli then you eat vegetable

converse: if you eat vegetables then you eat broccoli

inverse: if you don't eat broccoli then you don't eat vegetables

contrapositive: if you don't eat vegetables then you don't eat broccoli

Step-by-step explanation:

converse: q to p

inverse: not p not q

contrapositive: not q not p

7 0
3 years ago
Given the following inverse variation find the missing value: (5,-8) (20, y) find the missing value
forsale [732]
This answer is pretty simple. you see (5,-8) and (20,y). well the 20 is 4 times the 5 on the x value so multiply the y value by 4 to get your answer which Y=-32 in the 2nd corrdenants.
6 0
3 years ago
If one-sixth of a number plus one-third returns two-thirds of that number What is the number
Solnce55 [7]

Answer:

x= \frac{2}{3}

Step-by-step explanation:

Let the number be x

Given

\frac{1}{6}x + \frac{1}{3} = \frac{2}{3}x

Required

Find x

\frac{1}{6}x + \frac{1}{3} = \frac{2}{3}x

Collect Like Terms

\frac{1}{6}x -  \frac{2}{3}x = - \frac{1}{3}

Take LCM

\frac{1 - 4}{6}x = \frac{-1}{3}

\frac{- 3}{6}x = \frac{-1}{3}

Multiply both sides by 6

6 * \frac{- 3}{6}x = \frac{-1}{3} * 6

-3x= -2

Divide both sides by -3

\frac{-3x}{-3}= \frac{-2}{-3}

x= \frac{2}{3}

Hence, the number is \frac{2}{3}

7 0
3 years ago
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