Answer: angle g
Step-by-step explanation: Angle G is smaller than angle P. Angle G is larger than angle P. Angle G is congruent to angle N. 2 Consider the triangle.
Answer: 0.9649
Step-by-step explanation:
Let A denote the event that the days are cloudy and B denotes the event that the days are rainy.
Given : For the month of March in a certain city, the probability that days are cloudy :
Also in the month of March in the same city,, the probability that the days are cloudy and rainy :
Now by using the conditional probability, the probability that a randomly selected day in March will be rainy if it is cloudy will be :-

![\Rightarrow\ P(B|A)=\dfrac{0.55}{0.57}\\\\=0.964912280702\approx0.9649\ \ \text{[Rounded to four decimal places.]}](https://tex.z-dn.net/?f=%5CRightarrow%5C%20P%28B%7CA%29%3D%5Cdfrac%7B0.55%7D%7B0.57%7D%5C%5C%5C%5C%3D0.964912280702%5Capprox0.9649%5C%20%5C%20%5Ctext%7B%5BRounded%20to%20four%20decimal%20places.%5D%7D)
Hence, the probability that a randomly selected day in March will be rainy if it is cloudy = 0.9649
<span>3x^2+14x+8 = </span>(3x+2)(x+4)
Exponents are not particularly mysterious. They show repeated multiplication. That is ...
... c⁴ = c·c·c·c
... w² = w·w
Then the factor inside parentheses is ...
... 8·c·c·c·c·w·w
The exponent outside parentheses tells you the number of times this is repeated as a factor:
... (8c⁴w²)² = (8·c·c·c·c·w·w)(8·c·c·c·c·w·w)
... = 8·8·c·c·c·c·c·c·c·c·w·w·w·w = 64c⁸w⁴
_____
You can take advantage of the fact that multiplication is repeated addition, so the exponents of the various factors can be found by multiplying the outside exponent by the inside exponents.
