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katovenus [111]
3 years ago
9

Let P be a point between points S and T on 2004-01-01-02-00_files/i0120000.jpg. If ST = 21, SP = 3b – 11, and PT = b + 4, solve

for b.
A. –7
B. 7
C. 14
D. 32
Mathematics
1 answer:
tigry1 [53]3 years ago
8 0
I think its C.Hope this helps

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To go on a summer trip Manuel borrows $200. He makes no payments until the end of 4 years, when he pays off the entire loan. The
belka [17]

Answer:

A)40

B)240

Step-by-step explanation:

5% of 200 is 10

10*4 year=$40 interest

200+40=240 which is total

Im pretty sure

7 0
3 years ago
| -11 - (-8) | = <br> Please simplify and show work
Karolina [17]

Answer:

-3 should be your answer

Step-by-step explanation:

hope that helped :D

3 0
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A principal of $3900 is invested at 7.5% interest compounded annually how much will the investment be worth after 9 years
Paha777 [63]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$3900\\ r=rate\to 7.5\%\to \frac{7.5}{100}\dotfill &0.075\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &9 \end{cases} \\\\\\ A=3900\left(1+\frac{0.075}{1}\right)^{1\cdot 9}\implies A=3900(1.075)^9\implies A\approx 7477.23

7 0
2 years ago
A company is trying to determine how many Valentine’s Day cards to produce. The cost of printing x cards is $2 million +0.70x. F
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4 0
3 years ago
The perimeter of a rectangle is twice the sum of its lenght and its width. The perimeter is 34 meters and its lenght is 2 meters
Nostrana [21]

Answer:

The width of the rectangle is 5 meters, while the length of the rectangle is 12 meters.

Step-by-step explanation:

Given that the perimeter of a rectangle is twice the sum of its lenght and its width, and the perimeter is 34 meters and its lenght is 2 meters more than twice its width, to determine the length and width of the rectangle the following calculation must be done:

(2X + 2 + X) x 2 = 34

(3X + 2) x 2 = 34

6X + 4 = 34

6X = 34 - 4

X = 30/6

X = 5

(2x5 + 2 + 5) x 2 = 34

(10 + 2 + 5) x 2 = 34

17 x 2 = 34

34 = 34

Therefore, the width of the rectangle is 5 meters, while the length of the rectangle is 12 meters.

4 0
3 years ago
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