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NeTakaya
3 years ago
14

The number of a two dollar bill i need to pay for a purchase is 9 more than the number of 5 dollar bills i need to pay for the s

ame purchase what is the cost of the purchase?
Mathematics
1 answer:
melisa1 [442]3 years ago
5 0

Answer:

$60

Step-by-step explanation:

Let's say we need t $2 bills and v $5 bills.

We need 9 more $2 bills than $5 bills, so:

t = 9 + v

We also know that the amount of money in t $2 bills is 2 * t = 2t. The amount of money in v + 9 $5 bills is 5 * (v + 9) = 5v + 45. These amounts are equal:

5v + 45 = 2t

Plug v + 9 in for t in 5v = 2t + 18:

5v = 2t + 18

5v = 2 * (9 + v) + 18

5v = 18 + 2v + 18

3v = 36

v = 12

We have 12 $5 bills, so that total cost is 12 * 5 = $60.

<em>~ an aesthetics lover</em>

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Artyom0805 [142]

Let's begin noting that a triangle is isosceles if and only if two of its angles are congruent. We can thus find the angle <ABP, recalling that the sum of the interior angles of a triangle is equal to 180°.

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Finally, let point K be the intersection between segments BC and PQ, and let's note that the triangle PQB is a right isosceles triangle, since all the angles in a square are equal to 90°, and the two triangles APB and BQC are congruent.

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goblinko [34]

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4 0
3 years ago
Read 2 more answers
What type of triangle is △STR? right triangle equilateral triangle isosceles triangle scalene triangle
Setler79 [48]

Answer:

C. Isosceles Triangle

Step-by-step explanation:

An Isosceles triangle is a type of triangle in geometry that has two sides of equal length.

From the figure attached, triangle STR has two sides of equal length which are;

1.) ST and

2.) TR

The two equal sides (ST and TR) are called legs while the third side is called the base of the triangle.

*P.S: I believe your question is based on the image attached

7 0
2 years ago
A 1000-liter (L) tank contains 500 L of water with a salt concentration of 10 g/L. Water with a salt concentration of 50 g/L flo
djverab [1.8K]

Answer:

a) y(t)=50000-49990e^{\frac{-2t}{25}}

b) 31690.7 g/L

Step-by-step explanation:

By definition, we have that the change rate of salt in the tank is \frac{dy}{dt}=R_{i}-R_{o}, where R_{i} is the rate of salt entering and R_{o} is the rate of salt going outside.

Then we have, R_{i}=80\frac{L}{min}*50\frac{g}{L}=4000\frac{g}{min}, and

R_{o}=40\frac{L}{min}*\frac{y}{500} \frac{g}{L}=\frac{2y}{25}\frac{g}{min}

So we obtain.  \frac{dy}{dt}=4000-\frac{2y}{25}, then

\frac{dy}{dt}+\frac{2y}{25}=4000, and using the integrating factor e^{\int {\frac{2}{25}} \, dt=e^{\frac{2t}{25}, therefore  (\frac{dy }{dt}+\frac{2y}{25}}=4000)e^{\frac{2t}{25}, we get   \frac{d}{dt}(y*e^{\frac{2t}{25}})= 4000 e^{\frac{2t}{25}, after integrating both sides y*e^{\frac{2t}{25}}= 50000 e^{\frac{2t}{25}}+C, therefore y(t)= 50000 +Ce^{\frac{-2t}{25}}, to find C we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions y(0)=10, so 10= 50000+Ce^{\frac{-0*2}{25}}

10=50000+C\\C=10-50000=-49990

Finally we can write an expression for the amount of salt in the tank at any time t, it is y(t)=50000-49990e^{\frac{-2t}{25}}

b) The tank will overflow due Rin>Rout, at a rate of 80 L/min-40L/min=40L/min, due we have 500 L to overflow \frac{500L}{40L/min} =\frac{25}{2} min=t, so we can evualuate the expression of a) y(25/2)=50000-49990e^{\frac{-2}{25}\frac{25}{2}}=50000-49990e^{-1}=31690.7, is the salt concentration when the tank overflows

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