The sides are 2x, 3x-5 and 4x+2
perimiter is the sum of the sides
a.
2x+3x-5+4x+2=63 is an equation
b.
solve
group like terms
2x+3x+4x-5+2=65
add like terms
9x-3=65
add 3 to both sides
9x=68
divide both sides by 9
x=68/9
2x=2(68/9)=136/9 in
3x-5=3(68/9)-5=(68/3)-5=(68/3)-(15/3)=53/3
4x+2=4(68/9)+2=272/9+2=272/9+18/2=290/9
the side lengths are 136/9in, 53/3in, and 290/9in
Answer:
the answer is 8 7/8
Step-by-step explanation:
Answer:
Step-by-step explanation:
(-2,2) ...x1 = -2 and y1 = 2
(4,6)..x2 = 4 and y2 = 6
midpoint formula :
m = ((x1 + x2) / 2 , (y1 + y2) / 2)
m = ((-2 + 4) / 2 , (2 + 6) / 2)
m = 2/2 , 8/2
m = (1,4) <===
Subtract the powers
c. 9-7 so 10^2
d. 8-1 so 5^7
Four and ninety four thousandths. You're welcome!