Answer: 8
Step-by-step explanation: You would have to divide 828/9. The answer would be 92. You would then subtract this number from 100 pages to get your answer.
One cubic mile represent the volume of a cube with sides length equal 1 mile
hope this helped
Answer:
Step-by-step explanation:
You need to complete the square.
C(x) = 0.02(x^2 - 1000x ...) + 11000
C(x) = 0.02 (x^2 - 1000x + 500^2) + 11000 - 5000
C(x) = 0.02 (x^2 - 1000x + 500^2) + 6000
C(x) = 0.02(x - 500)^2 + 6000
Now if you look at the answer you will find that the square is completed. That means that number of tractors you could produce is 500 at a cost of 6000
There is a flow to this question that you may have trouble understanding.
First of all the 500^2. That comes from taking 1/2 of 1000 and squaring it. That's what you need to complete the square.
Bur that is not what you have adding into the equation. Remember that there is a 0.02 in front of the brackets.
500^2 = 250000
0.02 * 250000 = 5000
So that number must be subtracted to make the square = 0. When you remove the brackets, you should get 11000 all in all.
So what you have outside the brackets is 11000 - 5000 = 6000
The rest is just standard for completing the square.
Answer:
a. 4 : 1
b. 2 students
c. 3 : 1
Step-by-step explanation:
a. There were 12 students who got a C and 3 students who got As. The ratio is therefore:
12 : 3
Take it to the lowest form by dividing both sides by 3:
= 4 : 1
b. There were 4 students with a D grade and 8 with a B. The ratio is:
= 4 : 8
Taken to the lowest form that would be:
= 1 : 2
This means that for every student receiving a D, 2 students received an A.
c. 12 students received a C and 4 students received a D. That ratio is therefore:
= 12 : 4
Take to the lowest form by dividing both sides by 4:
= 3 : 1
The electrical resistance of a wire varies as its length and inversely as the square of the diameter.
R = (k*L)/(d^2)
where k = proportionality constant
Since the two wires have the same material, their proportionality constant is same.
Equating that
(R1*d1^2)/L1 = (R2*d2^2)/L2
Given that R1 = 10 ohms, d1 = 1.2 mm or 0.0012 m, L1 = 18 m, d2 = 1.5 mm or 0.0015 m, L2 = 27 m, and R2 is unknown.
Therefore
[10*(0.0012^2)]/18 = [R2*(0.0015^2)]/27
R2 = 9.6 ohms
