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Sonja [21]
3 years ago
7

What is the square root of pi???

Mathematics
1 answer:
alex41 [277]3 years ago
4 0
1.77 if you need more just tell me. have a nice day
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Find the derivative of y= 1 / x​
givi [52]

Answer:

dy/dx = -1/x^{2}

Step-by-step explanation:

y = 1/x

dy/dx = d/dx(1/x)

=> dy/dx = d/dx(x^{-1})

=> dy/dx = -x^{-2}

=> dy/dx = -1/x^{2}

6 0
2 years ago
How do you divide a whole number by a fraction​
lord [1]

Answer:Multiply the denominator on the bottom of the fraction by the whole number you are dividing by.

To divide a fraction by a whole number, multiply the bottom of the fraction by this whole number.

The denominator on the bottom of the fraction is 7.

We will multiply 7 by 2.

7 × 2 = 14 and so, 6 / 7 ÷ 2 = 6 / 14 .

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Freddy went to the museum and bought a reduced copy of a painting he saw in a exhibit. If the actual painting is 12 inches high,
Snowcat [4.5K]

Answer:

It is probably 6 inches wide. I tried my best

Step-by-step explanation:

4 0
2 years ago
Please help me my homework is due tomorrow use the screen shot
Ad libitum [116K]

Answer:

1/5

Step-by-step explanation:

(5^7*5^5)/5^13 (when multiplying numbers with the same base, add the exponents)

= (5^12)/5^13 (when dividing exponents with the same base, subtract the exponents)

= 1/5^1 (anything to the first power is itself)

= 1/5

6 0
2 years ago
In a recent poll, 778 adults were asked to identify their favorite seat when they fly, and 492 of them chose a window seat. Use
seropon [69]

Answer:

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

p_v =P(Z>7.36)=9.19x10^{-14}  

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

Step-by-step explanation:

1) Data given and notation

n=778 represent the random sample taken

X=492 represent the people that chose a window seat.

\hat p=\frac{492}{778}=0.632 estimated proportion of people that chose a window seat.

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the majority of adults prefer window seats when they fly:  

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.632 -0.5}{\sqrt{\frac{0.5(1-0.5)}{778}}}=7.36  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>7.36)=9.19x10^{-14}  

5) Conclusion

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

6 0
3 years ago
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