Based on the CPCTC theorem, the congruences that are true about the given triangles are:
B. ∠K ≅ ∠S
C. KL ≅ ST
D. JK ≅ RS
<h3>What is the CPCTC Theorem?</h3>
According to the CPCTC theorem states that if two triangles are congruent to each other, then, all their corresponding parts will be congruent to each other.
Given that triangles JKL and RST are congruent to each other, therefore:
∠J ≅ ∠R
∠K ≅ ∠S
∠L ≅ ∠T
JK ≅ RS
KL ≅ ST
JL ≅ RT
Therefore, the congruences that would be true by CPCTC are:
B. ∠K ≅ ∠S
C. KL ≅ ST
D. JK ≅ RS
Learn more about the CPCTC theorem on:
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Answer:
( -1,2)
Step-by-step explanation:
The solution is where the two lines intersect
The intersect at x=-1 and y=2
( -1,2)
9) x.14 = 6.26 ==> 14x=156 ==> x=11.1
12) OAB = Right Triangle : (27+24)² = 24² + AB² (Pythagoras)
==> 51² =24² + AB² ==> 2,601 = 576 + AB² ==> AB² = 2,601 - 576 = 2,025
==> AB² = 2015 AND AB =√2025 = 45
Sorry I can't read the last page
Answer: Subtract 6 from both sides. Then, one would get 3x=15. Divde by 3 on both sides. x=5.
Step-by-step explanation:
Slope-intercept form:
y=mx+b
m=slope
b=y-intercept
Data of the first line:
m=-5
b=y-intercept=3 (y-intercept=it is the value of "y" when x=0)
y=-5x+3
A line perpendicular to the line y=mx+b will have the following slope:
m`=-1/m
Therefore: the line perpendicular to the line y=-5x+3 will have the following slope:
m´=-1/(-5)=1/5
Point-slope form of a line: we need a point (x₀,y₀) and the slope (m):
y-y₀=m(x-x₀)
We know, the slope (m=1/5) and we have a point (3,2) therefore:
y-y₀=m(x-x₀)
y-2=1/5(x-3) (point-slope form)
y-2=(1/5)x-3/5
y=(1/5)x-3/5+2
y=(1/5)x+7/5 (slope-intercept form)
Answer: the line perpendicular to the first line will be: y=(1/5)x+7/5
